如何通过蓝牙从Unity c#android应用程序发送字符串到Arduino？

当我尝试发送我的字符串并在arduino上验证它时,它不会传递任何if语句. device.send()是我在一个名为Android&的资产包中使用的方法.微调控制器/蓝牙技术调整.如何从Unity C#Android应用程序向我的arduino发送字符串并传递if语句？

Unity C#代码

device.send(System.Text.Encoding.ASCII.GetBytes(“0,0”));

Arduino代码

#include <Wire.h>
#include <Adafruit_MotorShield.h>
Adafruit_MotorShield AFMS = Adafruit_MotorShield(); 
Adafruit_StepperMotor *myMotor = AFMS.getStepper(200, 2);

#include <SoftwareSerial.h>
SoftwareSerial Bluetooth(10, 9); // RX, TX
//int LED = 13; // the on-board LED


String Data; // the data received

int LED = 12; // LED on bread board

int height;
void setup() {
  Bluetooth.begin(38400);
  Serial.begin(38400);
  Serial.println("Waiting for command...");
  Bluetooth.println("Send 1 to turn on the LED. Send 0 to turn Off");
  pinMode(LED,OUTPUT);

  AFMS.begin();  // create with the default frequency 1.6KHz


  myMotor->setSpeed(100);  // 10 rpm   

  }

void loop() {
  if (Bluetooth.available()){ //wait for data received
  Data=Bluetooth.read();
if(Data == "0,1"){  
  digitalWrite(LED,1);
  Serial.println("LED On!");
  Bluetooth.println("LED On!");
  Serial.println("Single coil steps");
   myMotor->step(500, FORWARD, SINGLE); 

   }
else if(Data == "0,0"){
   digitalWrite(LED,0);
   Serial.println("LED Off!");
   Bluetooth.println("LED Off!");
   myMotor->step(500, BACKWARD, SINGLE); 
   }
else{;}


delay(100);
}

解决方法:

我能够解决它.请记住,我使用的是名为Android& amp;的Un​​ity资产.微控制器/蓝牙技术调整,这是device.send()的来源.

C#代码

device.send(System.Text.Encoding.ASCII.GetBytes ("0,1" + '\n'));

Arduino代码

#include <SoftwareSerial.h>
SoftwareSerial Bluetooth(10, 9); // RX, TX
String data = "";
int LED = 12; 


void setup() {
  //Bluetooth module baud rate which I set using AT commands
  Bluetooth.begin(38400);
  //Serial baud rate which I use to communicate with the Serial Monitor in the Arduino IDE
  Serial.begin(9600);
  Serial.println("Waiting for command...");

  pinMode(LED,OUTPUT);
}

void loop() {

 if(Bluetooth.available() > 0) {
     data = Bluetooth.readStringUntil('\n');

     if (data == "0,1") {
         digitalWrite(LED,1);
         Serial.println("LED ON!"); 
 }
}

原文地址：https://codeday.me/bug/20190910/1801424.html