ruby – 使用rest-client更正get请求的语法

现在我可以提出如下要求：

user = 'xxx'  
token = 'xxx'  
survey_id = 'xxx'  
response = RestClient.get "https://survey.qualtrics.com/WRAPI/ControlPanel/api.php?Request=getLegacyResponseData&User=#{user}&Token=#{token}&Version=2.0&SurveyID=#{survey_id}&Format=XML"

但应该有一些更好的方法来做到这一点.我尝试过这样的事情：

response = RestClient.get "https://survey.qualtrics.com/WRAPI/ControlPanel/api.php",:Request => 'getLegacyResponseData',:User => user,:Token => token,:Version => '2.0',:SurveyID => survey_id,:Format => 'XML'</code>

及其变化(字符串代替键的符号,包括{和},使键小写等)但我试过的组合似乎都没有用.这里的语法是什么？

我尝试了下面的第一个建议.它没用.为了记录,这工作：

surveys_from_api = RestClient.get "https://survey.qualtrics.com/WRAPI/ControlPanel/api.php?Request=getSurveys&User=#{user}&Token=#{token}&Version=#{version}&Format=JSON"

但这不是：

surveys_from_api = RestClient.get "https://survey.qualtrics.com/WRAPI/ControlPanel/api.php",:params => {:Request => 'getSurveys',:Version => version,:Format => 'JSON'}

(我设置版本=’2.0′).

解决方法

您需要使用符号：params指定查询字符串参数.否则它们将用作标题.

使用params的示例：

response = RestClient.get "https://survey.qualtrics.com/WRAPI/ControlPanel/api.php",:params => {:Request => 'getLegacyResponseData',:Format => 'XML'}