Python直升机游戏不会更新分数

作为Pygame学习课程的一部分,我必须创建简单的直升机游戏,类似于飞扬的小鸟.
它也应该有一个得分计数-因此,每当您使用直升机穿越方块之间的距离时,得分应加1.
游戏逻辑和其他所有功能都可以正常工作,除了每次直升机通过积木不添加分数时,所有时间分数都显示为0.
下面是代码,任何人都可以帮助

import pygame
import time
from random import randint


black = (0,0)
white = (255,255,255)
pygame.init()
surfaceWidth = 1280
surfaceHeight = 720

imageHeight = 30
imageWidth = 60


surface = pygame.display.set_mode((surfaceWidth,surfaceHeight))
pygame.display.set_caption('EVGENY GAME')
#clock = frames per second
clock = pygame.time.Clock()

img = pygame.image.load('Helicopter.jpg')

def score(count):
    font = pygame.font.Font('freesansbold.ttf',20)
    text = font.render("Score: "+str(count),True,white)
    surface.blit(text,[0,0])



def blocks(x_block,y_block,block_width,block_height,gap):
    pygame.draw.rect(surface,white,[x_block,block_height])
    pygame.draw.rect(surface,y_block+block_height+gap,surfaceHeight])

def replay_or_quit():
    for event in pygame.event.get([pygame.KEYDOWN,pygame.KEYUP,pygame.QUIT]):
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()

        elif event.type == pygame.KEYDOWN:
            continue

        return event.key
    return None


def makeTextObjs(text,font):
    textSurface = font.render(text,white)
    return textSurface,textSurface.get_rect()

def msgSurface(text):
    smallText = pygame.font.Font('freesansbold.ttf',20)
    largeText = pygame.font.Font('freesansbold.ttf',150)

    titleTextSurf,titleTextRect = makeTextObjs(text,largeText)
    titleTextRect.center = surfaceWidth / 2,surfaceHeight / 2
    surface.blit(titleTextSurf,titleTextRect)

    typTextSurf,typTextRect = makeTextObjs('Press any key to continue',smallText)
    typTextRect.center = surfaceWidth / 2,((surfaceHeight / 2) + 100)
    surface.blit(typTextSurf,typTextRect)

    pygame.display.update()
    time.sleep(1)

    while replay_or_quit() == None:
        clock.tick()

    main()

def gameover():
    msgSurface('GAME OVER')

def helicopter(x,y,image):
    surface.blit(img,(x,))

# first constance = game over,while not true we are playing game

def main():
    x = 50
    y = 100
    y_move = 0

    x_block = surfaceWidth
    y_block = 0
    block_width = 100
    block_height = randint(0,surfaceHeight/2)
    gap = imageHeight * 8
    block_move = 3


    current_score = 0

    game_over = False
    while not game_over:#this will keep running until it hits pygame.quit
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                game_over = True
            if event.type == pygame.KEYDOWN:
                if event.key == pygame.K_UP:
                    y_move = -10
            if event.type == pygame.KEYUP:
                if event.key == pygame.K_UP:
                    y_move = 5
        y += y_move

        surface.fill(black)
        helicopter(x,img)

        score(current_score)


        blocks(x_block,gap)
        x_block -= block_move

        if y > surfaceHeight-40 or y < 0:
            gameover()

        if x_block < (-1*block_width):
            x_block = surfaceWidth
            block_height = randint(0,surfaceHeight/2)

        if x + imageWidth > x_block:
            if x < x_block + block_width:
                if y < block_height:
                    if x - imageWidth < block_width + x_block:
                        gameover()
        if x + imageWidth > x_block:
            if y + imageHeight > block_height+gap:
                gameover()
        if x < x_block and x > x_block-block_move:
            current_score += 1



        pygame.display.update()#update,updates specific area on display,flip - updates whole display
        clock.tick(100)#100 frames per second
main()
pygame.quit()    
quit()            enter code here

最佳答案

您的计分器永远不会更新,因为永远不会达到您的计分器条件.更改

if x < x_block and x > x_block-block_move:

至

if x_block >= x > x_block-block_move: