我知道答案似乎是按照
this post使用“WITH RECURSIVE”,但我只是没有得到它.
我有一个名为people的表,以及一个名为position_hierarchy的表. people表有一个唯一的id uperson_id和我们称为pcn的位置id和一个启用的标志(因为当有人离开并被替换时,他们的替换获得相同的pcn). position_hierarchy具有列pcn,另一列reports_to是层次结构中位于它们之上的人的pcn.我想要做的是给一个人的uperson_id,并在层次结构中找到他们上面的人的所有uperson_id,和/或给一个uperson_id和另一个人的uperson_id,并告诉第二个人是否拥有超过第一个人的监督职位.
该公司的总裁被指出是因为他们的pcn与他们的report_to相同. (不是我的决定 – 我会使用null reports_to)
到目前为止我想出的是:
with recursive parents (uperson_id,pcn,reports_to) as ( select p1.uperson_id,ph1.pcn,ph1.reports_to from people p1 join position_hierarchy ph1 on ph1.pcn = p1.pcn where reports_to != ph1.pcn and active_revoke_flag = '0' union all select p2.uperson_id,ph2.pcn,ph2.reports_to from people p2 join position_hierarchy ph2 on p2.pcn = ph2.pcn join parents pp on pp.pcn = ph2.reports_to ) select parents.* from parents where uperson_id = 'aaa3644';
但是返回5行,使用相同的uperson_id,pcn和reports_to(这似乎是正确的行数,但我希望每个级别的主管的uperson_id.我觉得我缺少一些非常基本的东西,我可能会打耳光当你告诉我我做错了什么时,我的脑袋.
我做了什么
基于Erwin Brandstetter’s answer,我修复了一些事情(主要是因为我没有弄清楚active_revoke_flag在哪个表中)并提出了:
with recursive p as ( select pcn,reports_to from position_hierarchy where pcn = (SELECT pcn FROM people WHERE uperson_id = 'aaa3644') union all select ph2.pcn,ph2.reports_to from p join position_hierarchy ph2 ON ph2.pcn = p.reports_to AND p.pcn != p.reports_to ) select p2.uperson_id,p2.active_revoke_flag,p.* from p join people p2 USING (pcn) where p2.active_revoke_flag = '0';
我会尝试这种自下而上的方法,从感兴趣的人开始,然后继续努力:
with recursive p as ( select p1.uperson_id,p1.pcn,ph1.reports_to from people p1 join position_hierarchy ph1 USING (pcn) where ph1.active_revoke_flag = '0' and p1.uperson_id = 'aaa3644' union all select p2.uperson_id,p2.pcn,ph2.reports_to from p join position_hierarchy ph2 ON ph2.pcn = p.reports_to AND ph2.active_revoke_flag = '0' join people p2 ON p2.pcn = ph2.pcn ) select * from p;
或者,更快,因为我们只加入一次人:
with recursive p as ( select pcn,reports_to from position_hierarchy where active_revoke_flag = '0' and pcn = (SELECT pcn FROM person WHERE uperson_id = 'aaa3644') union all select ph2.pcn,ph2.reports_to from p join position_hierarchy ph2 ON ph2.pcn = p.reports_to AND ph2.active_revoke_flag = '0' ) select p2.uperson_id,p.* from p join people p2 USING (pcn); -- assuming pcn is unique in table person
暂且不说:我确实发现你的设计有重复的pcn有点可疑.
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