如何通过关系多方面的复合主键持久化数据在关系的多方面

如何解决如何通过关系多方面的复合主键持久化数据在关系的多方面

我遇到了问题，我们将不胜感激。 我有一个可能存在关系的实体，在关系的许多方面大多具有复合主键。 例如，我有两个实体，例如Client和Client_User，并且Client与具有复合主键的Client_User关联，即client_id和user_id ，我想在使用Spring数据Jpa将数据持久存储到Client_User实体时将数据持久存储到Client实体。我的实体如下所示：

@Entity
@Table(name = "client")
public class ClientEntity implements Serializable {
   private int clientId;
   private int userId;
   private Collection<ClientUserEntity> clientUsersByClientId;

   // ...
   
   @OnetoMany(mappedBy = "clientByClientId",fetch = FetchType.LAZY)
   @Cascade(org.hibernate.annotations.CascadeType.SAVE_UPDATE)
   public Collection<ClientUserEntity> getClientUsersByClientId() {
        return clientUsersByClientId;
   }
   public void setClientUsersByClientId(Collection<ClientUserEntity> clientUsersByClientId) {
        this.clientUsersByClientId = clientUsersByClientId;
   }
}
    
@Entity
@Table(name = "client_user")
@IdClass(ClientUserEntityPK.class)
public class ClientUserEntity implements Serializable {
   private int clientId;
   private int userId;
        
   @Id
   @Column(name = "client_id")
   public int getClientId() {
       return clientId;
   }
   public void setClientId(int clientId) {
       this.clientId = clientId;
   }
        
   @Id
   @Column(name = "user_id")
   public int getUserId() {
      return userId;
   }
   public void setUserId(int userId) {
      this.userId = userId;
   }
  
   @ManyToOne
   @JoinColumn(name = "client_id",referencedColumnName = "client_id",nullable = false,insertable =false,updatable  =false)
   public ClientEntity getClientByClientId() {
      return clientByClientId;
   }
   public void setClientByClientId(ClientEntity clientByClientId) {
      this.clientByClientId = clientByClientId;
   }
}
        
public class ClientUserEntityPK implements Serializable {
   private int clientId;
   private int userId;
    
   @Column(name = "client_id")
   @Id
   public int getClientId() {
      return clientId;
   }
   public void setClientId(int clientId) {
      this.clientId = clientId;
   }
    
   @Column(name = "user_id")
   @Id
   public int getUserId() {
       return userId;
   }
   public void setUserId(int userId) {
       this.userId = userId;
   }
    
   @Override
   public boolean equals(Object o) {
       if (this == o) return true;
       if (o == null || getClass() != o.getClass()) return false;
       ClientUserEntityPK that = (ClientUserEntityPK) o;
       return clientId == that.clientId &&
              userId == that.userId;
   }
    
   @Override
   public int hashCode() {
       return Objects.hash(clientId,userId);
   }
}