如何解决在python中找到上一个/最后一个星期的星期五
| 例如1。假设我有一天4/30/07。那么我需要得到4/27/07。 例如2。假设我有一天6/29/07,那么我需要得到6/22/07。解决方法
假设
day
是datetime.date
或datetime.datetime
对象,则此代码为上周的星期五创建datetime
/date
对象:
friday = day - timedelta(days=day.weekday()) + timedelta(days=4,weeks=-1)
说明:timedelta(days=day.weekday())
是星期一和day
之间的偏移量,因此加4天并减去一周将获得上周的星期五。
当然,您可以简化此过程(+4d -1w = -3d
):
friday = day - timedelta(days=day.weekday() + 3)
注意:要获得timedelta
,请使用from datetime import timedelta
或仅使用import datetime
并使用datetime.timedelta
, 另一种简便的方法是使用python-dateutil。
要获取上一个星期五:
>>> from dateutil.relativedelta import relativedelta,FR
>>> from datetime import datetime
>>> datetime(2015,7,8) + relativedelta(weekday=FR(-1))
datetime.datetime(2015,3,0)
下一个星期五:
>>> datetime(2015,8) + relativedelta(weekday=FR(+1))
datetime.datetime(2015,10,0)
, 不特定于星期五,而是指定为一天“ taget_dayofweek \”(其中星期一为0,星期日为6)
from datetime import datetime
target_dayofweek = 4 # Friday
current_dayofweek = datetime.now().weekday() # Today
if target_dayofweek <= current_dayofweek:
# target is in the current week
endDate = datetime.now() - timedelta(current_dayofweek - target_dayofweek)
else:
# target is in the previous week
endDate = datetime.now() - timedelta(weeks=1) + timedelta(target_dayofweek - current_dayofweek)
, date_object = datetime.date.today()
from dateutil.relativedelta import relativedelta
previousWeekLastDay = date_object + relativedelta(weekday=SU(-1))
previousWeekFirstDay = previousWeekLastDay + relativedelta(weekday=MO(-1))
print(previousWeekFirstDay)
print(previousWeekLastDay)
previoustopreviousWeekLastDay1= date_object + relativedelta(weekday=SU(-2))
previoustopreviousWeekFirstDay1= previousWeekLastDay1 + relativedelta(weekday=MO(-1))
print(previoustopreviousWeekFirstDay1)
print(previoustopreviousWeekLastDay1)
, pandas.tseries.offsets中有很多选项
这是前一周的星期五。
from pandas.tseries.offsets import Week
f_dates = required_df.index - Week(1,weekday=4)
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