我有从大日志文件中提取的周数列表,它们是使用语法提取的:
$date --date="Wed Mar 20 10:19:56 2012" +%W; 12
我想创建一个简单的bash函数,可以将这些周数转换为日期范围.我想函数应该接受2个参数:$number和$year,例如:
$week() { ......... } $number=12; year=2012 $week $number $year "Mon Mar 19 2012" - "Sun Mar 25 2012"
使用GNU日期:
$cat weekof.sh function weekof() { local week=$1 year=$2 local week_num_of_Jan_1 week_day_of_Jan_1 local first_Mon local date_fmt="+%a %b %d %Y" local mon sun week_num_of_Jan_1=$(date -d $year-01-01 +%W) week_day_of_Jan_1=$(date -d $year-01-01 +%u) if ((week_num_of_Jan_1)); then first_Mon=$year-01-01 else first_Mon=$year-01-$((01 + (7 - week_day_of_Jan_1 + 1) )) fi mon=$(date -d "$first_Mon +$((week - 1)) week" "$date_fmt") sun=$(date -d "$first_Mon +$((week - 1)) week + 6 day" "$date_fmt") echo "\"$mon\" - \"$sun\"" } weekof $1 $2 $bash weekof.sh 12 2012 "Mon Mar 19 2012" - "Sun Mar 25 2012" $bash weekof.sh 1 2018 "Mon Jan 01 2018" - "Sun Jan 07 2018" $
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