使JAXB生成XML处理指令

我正在使用JAXB动态生成XML.

现在,我想使用XSL将其转换为HTML.我怎么能包括

<?xml-stylesheet type="text/xsl" href="">

在动态生成的XML中？

这里的所有解决方案都非常丑陋且冗长.只需在Mashaller对象中设置指定附加标题的行.

Marshaller jaxbMarshaller = ...
jaxbMarshaller.setProperty("com.sun.xml.bind.xmlHeaders","<?xml-stylesheet type='text/xsl' href='nameoffile.xsl' ?>");

此示例将使用样式表将XML对象输出到文件,并且很好地格式化元素以供人类阅读.对象myXmlObject属于MyXmlClass类,将被写入文件,由xslUrl给出的样式表格式化：

JAXBContext context = JAXBContext.newInstance(MyXmlClass.class);
Marshaller marshaller = context.createMarshaller();
//Need to use a Writer to marshal with the XSL
FileWriter fw = new FileWriter(file);
//Do this or else the XML is all one line and not human friendly...
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT,Boolean.TRUE);
marshaller.setProperty("com.sun.xml.bind.xmlHeaders","<?xml-stylesheet type='text/xsl' href=\"" +
        xslUrl +
        "\" ?>");
marshaller.marshal(myXmlObject,fw);