我创建了一个简单的类比表:
+----+-------+-------+ | id | sku_1 | sku_2 | +----+-------+-------+ | 1 | a1 | abcd | | 2 | a2 | a3 | | 3 | a3 | a1 | +----+-------+-------+ 3 rows in set (0.00 sec)
什么意思?这意味着具有物品abcd的产品具有与物品a1类似的物品,否则例如具有物品a3的产品具有与物品a1类似的物品.
如何以单篇文章递归获取此表中的所有产品?
我的解决方案是错的:
// Small Class to get analogs of products class Analogs { public function get_analogs($sku) { if (!$sku) return false; $link = mysql_connect('localhost','',''); mysql_select_db('test'); $sku = mysql_real_escape_string($sku,$link); $query = mysql_query("SELECT * FROM analogs WHERE sku_1='".$sku."' OR sku_2='".$sku."'"); while($analogs[]=mysql_fetch_assoc($query)) continue; return $analogs; } public function MixedAnalogs($sku) { if (!$sku) return false; $link = mysql_connect('localhost',$link); $query = mysql_query("select sku_1 sku from analogs where sku_2 = '$sku' UNION select sku_2 sku from analogs where sku_1 = '$sku'"); while($analogs[]=mysql_fetch_assoc($query)) continue; return $analogs; } } $mixed_analogs = AnalogsMix('abcd',$ids=array()); echo "<pre>"; print_r($mixed_analogs); echo "</pre>"; // Recursive function to get analogs of analog function AnalogsMix($sku,$ids=array()) { $class_analogs = new Analogs(); $analogs = $class_analogs->get_analogs($sku); foreach ($analogs as $analog) { $cross = null; if ($analog['sku_1']==$sku) { $cross->sku = $analog['sku_2']; } else { $cross->sku = $analog['sku_1']; } $cross->id = $analog['id']; if (!in_array($analog['id'],$ids)) { $ids[] = $analog['id']; $mixed[] = AnalogsMix($cross->sku,$ids); } } if (isset($mixed)) { return $mixed; } else { return false; } }
SQL UNION
select sku_1 sku from analogs where sku_2 = $yourid union select sku_2 sku from analogs where sku_1 = $yourid
然后你将得到结果只有类似物的ID.
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