有什么方法可以简化此代码？ ＆像我显示的示例代码一样插入布尔值会更好吗？

如何解决有什么方法可以简化此代码？ ＆像我显示的示例代码一样插入布尔值会更好吗？

这是我的代码，该代码从0到10之间选择一个随机数供用户猜测。

//guess the number game
//my code
#include <iostream>
#include <string>
#include <cstdlib>
#include <ctime>

using namespace std;

int main()
{
  unsigned int secretNumber; 
  int guess;
  int maxNumber = 10;
  int maxTries = 4;
  int numTries = 1;


  srand(static_cast<unsigned int>(time(0)));
  secretNumber = (rand() % 10)+ 1;
  cout << "GUESS A NUMBER FROM 0 TO 10!!\n";
    do {
      cout << "\nGuess: \n";
      cin >> guess;
  
      if (guess < secretNumber)
      {
          cout << "too low:(:(!!      ";
          numTries++;
          cout << "Guesses Left: " << maxTries - numTries;
      } ***//Would it be better to add a bool in the condition?***
  
      else if (guess > secretNumber && guess <= maxNumber)
      {
          cout << "Too high:D:D!!      ";
          numTries++;
          cout << "Guesses Left: " << maxTries - numTries;
      }
  
      else if (guess > maxNumber)
      {
          cout << "Do you know how to count to 10?\n";
          cout << "Only from 0 TO 10!!  ";
          numTries++;
          cout << "Guesses Left: " << maxTries - numTries;
      }
  
      else {
          cout << "WOW! you GUESSED IT?! AMAZING!!!!";
          cout << "You're right! the number is " << guess; 
          cout << "\nYou got it right in " << numTries << " guesses!!!";
      }
  
      if (numTries == maxTries)
      {
          cout << "\n\nYou LOOSE :( LOL!";
      }
  
  
  } while (guess != secretNumber && maxTries != numTries);

  return 0;
} 

这是教师的代码，它更简单并且包含bool变量。 我以前的代码应该像这样简单吗？

// Example program
// Teacher's code
#include <iostream>
#include <string>
#include <cstdlib>
#include <ctime>

using namespace std;

int main()
{
  int secretNumber = 7; 
  int guess;
  int numTries = 0;
  int maxTries = 3;
  bool outOfGuesses = false;

  while (secretNumber != guess && !outOfGuesses)
  {
      if (numTries != maxTries)
      {cout << "Guess a Number: ";
      cin >> guess;
      numTries++;}
  
      else 
      {
          outOfGuesses = true;
      }
  }

  if (outOfGuesses)
  {
      cout << "You loose!";
  }
  else 
  {
      cout << "You win!";
  }
  return 0;
}

//我的代码是否像老师的代码一样高效和简单？ //是否有更简单的方法可以完成我打算在代码中执行的操作？