C ++中的线程安全数据结构

如何解决C ++中的线程安全数据结构

就像使线程安全的C ++数据结构一样。

struct infos{
  int crowdinfos[10][horGridNums*verGridNums];
  int cameraSourceID;
  static int idx;
  std::mutex mutex;
  
};

mutex.lock和解锁将用于线程安全。

编辑： 在我的头文件中，我将获得一个信息向量。

std::vector<infos> c_infos;

当我使用g ++进行构建时，出现错误

/usr/include/c++/7/bits/stl_construct.h:75:7: error: use of deleted function ‘infos::infos(const infos&)’
     { ::new(static_cast<void*>(__p)) _T1(std::forward<_Args>(__args)...); }
       ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
In file included from gstdsexample.cpp:29:0:
gstdsexample.h:66:8: note: ‘infos::infos(const infos&)’ is implicitly deleted because the default definition would be ill-formed:
 struct infos{
        ^~~~~
gstdsexample.h:66:8: error: use of deleted function ‘std::mutex::mutex(const std::mutex&)’

构建中的整个日志信息如下。

-fPIC -DDS_VERSION="5.0.0" -I /usr/local/cuda-10.2/include -I ../../includes -pthread -I/usr/include/gstreamer-1.0 -I/usr/include/orc-0.4 -I/usr/include/gstreamer-1.0 -I/usr/include/glib-2.0 -I/usr/lib/aarch64-linux-gnu/glib-2.0/include -I/usr/include/opencv4/opencv -I/usr/include/opencv4
g++ -c -o gstdsexample.o -fPIC -DDS_VERSION=\"5.0.0\" -I /usr/local/cuda-10.2/include -I ../../includes -pthread -I/usr/include/gstreamer-1.0 -I/usr/include/orc-0.4 -I/usr/include/gstreamer-1.0 -I/usr/include/glib-2.0 -I/usr/lib/aarch64-linux-gnu/glib-2.0/include -I/usr/include/opencv4/opencv -I/usr/include/opencv4 gstdsexample.cpp
In file included from /usr/include/c++/7/bits/stl_tempbuf.h:60:0,from /usr/include/c++/7/bits/stl_algo.h:62,from /usr/include/c++/7/algorithm:62,from /usr/include/opencv4/opencv2/core/base.hpp:55,from /usr/include/opencv4/opencv2/core.hpp:54,from /usr/include/opencv4/opencv2/imgproc.hpp:46,from /usr/include/opencv4/opencv2/imgproc/imgproc.hpp:48,from gstdsexample.h:30,from gstdsexample.cpp:29:
/usr/include/c++/7/bits/stl_construct.h: In instantiation of ‘void std::_Construct(_T1*,_Args&& ...) [with _T1 = infos; _Args = {const infos&}]’:
/usr/include/c++/7/bits/stl_uninitialized.h:83:18:   required from ‘static _ForwardIterator std::__uninitialized_copy<_TrivialValueTypes>::__uninit_copy(_InputIterator,_InputIterator,_ForwardIterator) [with _InputIterator = __gnu_cxx::__normal_iterator<const infos*,std::vector<infos> >; _ForwardIterator = infos*; bool _TrivialValueTypes = false]’
/usr/include/c++/7/bits/stl_uninitialized.h:134:15:   required from ‘_ForwardIterator std::uninitialized_copy(_InputIterator,std::vector<infos> >; _ForwardIterator = infos*]’
/usr/include/c++/7/bits/stl_uninitialized.h:289:37:   required from ‘_ForwardIterator std::__uninitialized_copy_a(_InputIterator,_ForwardIterator,std::allocator<_Tp>&) [with _InputIterator = __gnu_cxx::__normal_iterator<const infos*,std::vector<infos> >; _ForwardIterator = infos*; _Tp = infos]’
/usr/include/c++/7/bits/stl_vector.h:331:31:   required from ‘std::vector<_Tp,_Alloc>::vector(const std::vector<_Tp,_Alloc>&) [with _Tp = infos; _Alloc = std::allocator<infos>]’
gstdsexample.cpp:444:40:   required from here
/usr/include/c++/7/bits/stl_construct.h:75:7: error: use of deleted function ‘infos::infos(const infos&)’
     { ::new(static_cast<void*>(__p)) _T1(std::forward<_Args>(__args)...); }
       ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
In file included from gstdsexample.cpp:29:0:
gstdsexample.h:66:8: note: ‘infos::infos(const infos&)’ is implicitly deleted because the default definition would be ill-formed:
 struct infos{
        ^~~~~
gstdsexample.h:66:8: error: use of deleted function ‘std::mutex::mutex(const std::mutex&)’
In file included from /usr/include/c++/7/mutex:43:0,from /usr/include/opencv4/opencv2/core/utility.hpp:62,from /usr/include/opencv4/opencv2/core.hpp:3291,from gstdsexample.cpp:29:
/usr/include/c++/7/bits/std_mutex.h:97:5: note: declared here
     mutex(const mutex&) = delete;

在Struct内部使用的正确方法是什么？

解决方法

由于您还没有完全发布代码，所以我不确定您的问题是什么。因此，请改用下面的示例。

这是我将互斥量用于队列的方式。通过查看它，您可以使自己的结构适应您想要完成的任务。

class Queue {
public:
    Queue() = default;

    /**
     * Push a message to the queue.
     */
    void push(const std::array<int,4>& message) {
        while (true) {
            std::unique_lock<std::mutex> locker(mu);
            cond.wait(locker,[this](){ return buffer_.size() < size_; });
            buffer_.push_back(message);
            locker.unlock();
            cond.notify_all();
            return;
        }
    }

    /**
     * Pop a message off the queue.
     */
    bool pop(std::array<int,4>& value) {
        while (true) {
            std::unique_lock<std::mutex> locker(mu);
            if (buffer_.size() == 0) {
                return false;
            }
            value = buffer_.front();
            buffer_.pop_front();
            locker.unlock();
            cond.notify_all();
            return true;
        }
    }

private:
    std::mutex mu;
    std::condition_variable cond;

    std::deque<std::array<int,4>> buffer_;
    const unsigned int size_ = 200;
    
};

简而言之，只要您希望线程安全地访问某些对象，就可以执行以下操作：

std::unique_lock<std::mutex> locker(mu);
            
//Add Your code on the object you want thread safe access to.

            locker.unlock();
            cond.notify_all();

重要的是，您如上所述只能在更衣室/解锁中访问要线程安全访问的对象，并如上所述通知所有等待该对象的人。

请查看您的错误消息：

‘infos::infos(const infos&)’ is implicitly deleted because the default definition would be ill-formed:  struct infos{