为什么我的用于推送通知的云功能无法正常工作

如何解决为什么我的用于推送通知的云功能无法正常工作

在我的flutter应用程序中，我试图使用云功能配置推送通知，但是我遇到了一个问题，即我的Firebase控制台根据预期的云功能触发器发送了通知，但无法在以下位置接收通知我的Android模拟器。我在控制台上记录了该消息，但我注意到Firebase控制台已成功发送了该通知消息，但在模拟器上却没有收到该消息。当我尝试在主页上打印消息时，我得到了： 在消息上：{body：null，标题：null}，数据：{收件人：sjjsjnhhaksdijadjifjhhabdbfhakdjf}}，我的模拟器没有显示带有消息的小吃店。这些是我下面的代码。请我帮忙。

this part of the cloud function code to listens to new document on
the`activity path and to send notification 

exports.onCreateActivityNotification = functions.firestore
.document('/activities/{userId}/userActivities/{userActivities}')
 .onCreate(async (snapshot,context) => {
 console.log('activity notification created',snapshot.data());
 //getting user connected to the activity
 const userId = context.params.userId;
 const createdActivityItem = snapshot.data();
 const usersRef = admin.firestore().doc(`users/${userId}`);
 const doc = await usersRef.get();
 const androidNotificationToken = 
 doc.data().androidNotificationToken;
  //checks if user has an androidnotification token
 if(androidNotificationToken){
 //sennds notification if users has a token
   sendNotification(androidNotificationToken,createdActivityItem )
  } else {
   console.log('no notification token');
  }
   //function for sending notification
 function sendNotification(androidNotificationToken,userActivities)
  {
  let body;
     switch (userActivities){
      case userActivities.comment !== null:
        body = `${userActivities.fromUserId} commented  : 
      ${userActivities.comment}`
        break;
        case userActivities.comment === null:
        body = `${userActivities.fromUserId} liked your punch`
        break;
        default: 
         break;
        }
     //creates message for push notification
    const message = {
    notification: {body: body},token: androidNotificationToken,data: {recipient: userId},};
    //sends message with admin.messaging()
    admin
   .messaging()
   .send(message)
   .then(response => {
   return console.log('message sent',response);
    }).catch(error =>{
    console.log('error sending message',error);
   })
 }

}）;

//code for the home page. This is the part of the code to display the 
// notification on the emulator  

//configuring the notification
_configureNotification() {
final String currentUserId =
    Provider.of<UserData>(context,listen: false).currentUserId;
if (Platform.isIOS) getIosPermission();
_firebaseMessaging.getToken().then((token) => {
      print('firebase messaging token: $token'),//associating device token with current user
      usersRef
          .document(currentUserId)
          .updateData({'androidNotificationToken': token})
    });
//displaying notification from cloud function
    _firebaseMessaging.configure(
  onMessage: (Map<String,dynamic> message) async {
    print('on message: $message\n');
    final String recipientId = message['data']['recipient'];
    final String body = message['notification']['body'];
     //checking if recipientId is equal to currentuserId before 
      //sending notification 
    if (recipientId == currentUserId) {
      print('notification shown');
      Flushbar(
        margin: EdgeInsets.all(8),// flushbarPosition: FlushbarPosition.TOP,title: widget.user.name,messageText: Column(
          children: <Widget>[
            RichText(
              text: TextSpan(children: [
                TextSpan(
                    text: body,style: TextStyle(
                        fontSize: 14,// fontWeight: FontWeight.bold,color: Colors.black)),]),overflow: TextOverflow.ellipsis,),SizedBox(
              height: 30,],icon: Icon(Icons.info_outline,size: 28.0,color: 
      Colors.blue),duration: Duration(seconds: 3),leftBarIndicatorColor: Colors.blue,)..show(context);
    }
    print('notification not shown');
  },);

}

//getting ios permission
getIosPermission() {
_firebaseMessaging.requestNotificationPermissions(
    IosNotificationSettings(alert: true,sound: true,badge: true));
_firebaseMessaging.onIosSettingsRegistered.listen((settings) {
  print('settings registered: $settings');
});

}

解决方法

https://stackoverflow.com/a/23443757/9323100

查看此答案！仿真器并不总是接收通知。另外，请务必在设备上尝试