如何在laravel中雄辩地进行此查询？

如何解决如何在laravel中雄辩地进行此查询？

我有这个数据库： [数据库模型]

这是我想在Laravel中进行的查询：

SELECT 
  product_translations.name,product_translations.description,products.ean_code
FROM product_translations,products,languages
WHERE product_translations.language_id = languages.id
  AND products.id = product_translations.product_id
  AND languages.language_code = "en";

Laravel中的关系

class Product extends Model
{
    public function translations ()
    {
        return $this->hasMany(ProductTranslation::class,'product_id');
    }
}

class ProductTranslation extends Model
{
    public function product()
    {
        return $this->belongsTo(Product::class,'product_id');
    }

    public function language()
    {
        return $this->belongsTo(Language::class,'language_id');
    }
}

class Language extends Model
{
    public function ProductTranslations()
    {
        return $this->hasMany(ProductTranslation::class,'language_id');
    }

 }

这是正确的吗？原始查询有效。 谢谢

解决方法

您使用的查询语法是一种旧式语法，将为表生成内部联接。使用laravel，您可以使用内置方法从相关模型中查询数据。

对于您的问题，我相信您需要产品列表，但需要特定的翻译

$products = Product::with(['translations' => function($query)
{
    $query->join('product_translations as pt','products.id','=','pt.cart_id')
          ->join('languages as l','l.id','pt.language_id')
          ->where('l.language_code','en')
          ->first();

}])->get();

或者，如果您想使用查询构建器，则可以写为

$products = DB::table('products AS p')
    ->select([
    'p.id','p.is_organic','pt.name','pt.description','pt.ean_code'
    ])
    ->join('product_translations AS pt','pt.product_id','p.id' )
    ->join('languages AS l','pt.language_id','l.id')
    ->where('l.language_code','en')
    ->get();

在SQL中

SELECT 
  p.id,p.is_organic,pt.name,pt.description,pt.ean_code
FROM products p 
INNER JOIN product_translations as pt ON pt.product_id = p.id
INNER JOIN languages l ON pt.language_id = l.id
  WHERE l.language_code = "en";