使用Tidyr 数据

如何解决使用Tidyr 数据

我有一个包含植被数据的数据框。列是物种名称,行是它们在每个站点的相对丰度。地点,地块代码和年份也是变量。数据如下:

Site Code Year speca specb specc 
A     A1  2001   0     1     10   
A     A2  2001   5     5     15
B     B1  2001   0     5     20
B     B1  2004   15    75    0
C     C1  2006   50    0     15

我希望数据表看起来像这样:

species A1_2001 A2_2001 B1_2001 B1_2004 C1_2006
speca   0       5       0       15      50
specb   1       5       5       75      0
specc   10      15      20      0       15

我尝试使用tidyr:pivot_longer函数,但这没有得到我想要的结果。

tidyr::pivot_longer(df,4:length(df),names_to = "species",values_to = "abundance")

有没有一种方法可以以代码友好的方式实现,最好使用tidyrtidyverse)?

解决方法

我们将其重塑为“长”格式,然后使用<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <meta name="viewport" content="width=device-width,initial-scale=1.0"> <link rel="stylesheet" href="style.css"> <link href="https://fonts.googleapis.com/css2?family=Lora:wght@400;500&display=swap" rel="stylesheet"> <title>Implementing a Layout using HTML & CSS</title> </head> <body> <nav> <ul> <li><a href="">home</a></li> <li><a href="">about us</a></li> <li><a href="">contact</a></li> <li><a href="">company</a></li> <li><a href="">services</a></li> </ul> </nav> <div class="name"> <div class="title">TechCorporate</div> <div class="title2">Free PSD Website Template</div> <div class="contact"> <p>Tel: xxxxxxx xxxxxxxx</p> <p>Mail: info@domain.com</p> </div> </div> <div class="blue"> <div class="tech">TECHNOLOGY</div> <div class="box1"> <p>Lorem ipsum dolor sit amet das</p> <p>Lorem ipsum dolor sit amet consectetur adipisicing elit. Placeat,unde debitis quibusdam quas accusantium ipsa officia quo iste delectus modi voluptatibus harum rem saepe quod maxime quam. Velit,beatae quos ipsum dolor sit amet consectetur elit. Placeat,unde debitis.</p> </div> </div> <div class="box2">Todays Technology »</div> </body> </html>

做“宽”格式
pivot_wider

数据

library(dplyr)
library(tidyr)
df %>%
  pivot_longer(cols = starts_with('spec'),names_to = 'species') %>% 
  unite(CodeYear,Code,Year) %>%
  select(-Site) %>%
  pivot_wider(names_from = CodeYear,values_from = value)
# A tibble: 3 x 6
#  species A1_2001 A2_2001 B1_2001 B1_2004 C1_2006
#  <chr>     <int>   <int>   <int>   <int>   <int>
#1 speca         0       5       0      15      50
#2 specb         1       5       5      75       0
#3 specc        10      15      20       0      15
,

在data.table中:

library(data.table)

DT <- data.table(Site = c('A1','A2','B1','C1'),Year = c(2001,2001,2004,2006),speca = c(0,5,15,50),specb = c(1,75,0),specc = c(10,20,15))

DT <- melt(DT,id.vars = c('Site','Year'),measure.vars = c('speca','specb','specc'),variable.name = 'species')

DT <- dcast(DT,species ~ Site + Year,value.var = c('value'))

> DT

   species A1_2001 A2_2001 B1_2001 B1_2004 C1_2006
1:   speca       0       5       0      15      50
2:   specb       1       5       5      75       0
3:   specc      10      15      20       0      15
,

您主要需要pivot_wider()才能跟随pivot_longer()

library(tidyverse)
df <- tribble(~Site,~Code,~Year,~speca,~specb,~specc,"A","A1",1,10,"A2","B","B1","C","C1",2006,50,15)

df %>% 
  mutate(Code = paste(Code,Year,sep = "_")) %>% 
  select(-Site,-Year) %>% 
  pivot_longer(starts_with("spec"),names_to = "species",values_to = "abundance") %>% 
  pivot_wider(names_from = Code,values_from = abundance)

结果是

# A tibble: 3 x 6
  species A1_2001 A2_2001 B1_2001 B1_2004 C1_2006
  <chr>     <dbl>   <dbl>   <dbl>   <dbl>   <dbl>
1 speca         0       5       0      15      50
2 specb         1       5       5      75       0
3 specc        10      15      20       0      15

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