从C ++ 11线程获取Win32 API的本机线程句柄

如何解决从C ++ 11线程获取Win32 API的本机线程句柄

我想在windows.h上使用std::thread中的某些Win32 API函数。首先，我正在创建并启动std::thread。然后，我想通过使用native_handle()获取句柄在其上使用Win32 API函数。

// suspend_thread.cpp

#include <windows.h>
#include <iostream>
#include <thread>

void foo()
{
    unsigned int counter = 1;
    while (counter <= 5)
    {
        // do some work and finish after about 5 seconds
        std::cout << "Running... " << counter << "/5" << std::endl;
        counter++;
        std::this_thread::sleep_for(std::chrono::seconds(1));
    }
    std::cout << "Done!" << std::endl;
}

int main(void)
{
    std::cout << "Starting thread..." << std::endl;
    std::thread my_thread(foo);

    std::cout << "Waiting 3 seconds..." << std::endl;
    std::this_thread::sleep_for(std::chrono::seconds(3));

    DWORD result = SuspendThread((void*) my_thread.native_handle());
    if (result != -1) std::cout << "Successfully suspended thread!" << std::endl;
    else std::cout << "Failed to suspend thread! Error: " << GetLastError() << std::endl;

    my_thread.join();
    return 0;
}

如果我不将native_handle()的结果强制转换为void* ...

DWORD result = SuspendThread(my_thread.native_handle());

...代码无法编译，因为SuspendThread()需要一个指针。

.\suspend_thread.cpp:25:57: error: invalid conversion from 'std::thread::native_handle_type' {aka 'unsigned int'} to 'HANDLE' {aka 'void*'} [-fpermissive]

现在，如果我编译并运行第一个示例，则会得到以下结果。

PS> g++ -std=c++11 -pthread suspend_thread.cpp -o suspend_thread.exe
PS> ./suspend_thread.exe
Starting thread...
Waiting 3 seconds...
Running... 1/5
Running... 2/5
Running... 3/5
Failed to suspend thread! Error: 6
Running... 4/5
Running... 5/5
Done!

我试图在线程运行时挂起它，但是该函数失败，错误代码为6，根据文档，它代表...

ERROR_INVALID_HANDLE (0x6): The handle is invalid.

...显然，这不是将句柄传递给Win32 API函数的正确方法。

我知道我可以不用Win32 API来以其他方式暂停和恢复线程。