正则表达式选择带有空格的单词来代替

如何解决正则表达式选择带有空格的单词来代替

我在JS中有一个字符串，需要在其中将'添加到值中。 示例：task: task one,client: Mr jhon将转换为 task:'task one',client: 'Mr Jhon'

将这些字符串视为用户输入的搜索查询。然后将其发送到支持者进行搜索。值需要包含在'

中

复杂性

• taskname: one two three,client: Mr Jhon不能超过2个字
• taskname: one two,client: Mr Jhon超过1个空格
• taskname:one,client: Mr Jhon可以是没有空格的单字
• priority:1,groupname: Mr Singh的名称可以是任何东西
• priority:1,task: Mr Singh,planet:pluto,done:Yes可以有2个以上的数据点

我正在使用以下代码在Javascript中转换字符串。

let myStr = `taskname: task one`
myStr = `${myStr},`
const finalStr = myStr.replace(/:((?:\w*\s*)+),/g,`:'$1',`)
console.log(finalStr)

问题1：正则表达式是否有效？

PS：我将在Node JS服务器中使用它。

解决方法

也许这样的事情对您有用

let myStr = `taskname: task  one,client: Mr jhon
taskname: one two three,client: Mr Jhon there can be more than 2 words
taskname: one     two,client: Mr Jhon more than 1 space
taskname:one,client: Mr Jhon can be singe word without space
priority:1,groupname: Mr Singh the name of can be anything
priority:1,task: Mr Singh,planet:pluto,done:Yes There can be more than 2 data points`;

const finalStr = myStr.replace(
  /((?<=^\w+\:)(.*?)(?=\,)|(?<=\w+\:)(.*?)(?=\,)|(?<=\w+\:)(.*?)$)/gim,(match) => `'${match.trim()}'`
);

console.log(finalStr);

,

这应该可以正常工作：

let myStr = `taskname: one two three,client: Mr Jhon
taskname: one     two,client: Mr Jhon
taskname:one,client: Mr Jhon
priority:1,groupname: Mr Singh
priority:1,done:Yes`;

const finalStr = myStr.replace(/([^,:\n]+):\s*([^,:\n]+)/g,`$1:'$2'`)
console.log(finalStr)

输出：

taskname:'one two three',client:'Mr Jhon'
taskname:'one     two',client:'Mr Jhon'
taskname:'one',client:'Mr Jhon'
priority:'1',groupname:'Mr Singh'
priority:'1',task:'Mr Singh',planet:'pluto',done:'Yes'