使用数据框绘制温度与20年中的月份的关系图

如何解决使用数据框绘制温度与20年中的月份的关系图

我正在尝试用单独的线条绘制多年的数据；月vs平均气温。我试图举一个例子，说明我从中获取数据帧以及到目前为止的代码。我想到的一切都会返回错误...一般来说，我是编码和python的新手，只有maltab才是经验。如果您能解释为什么要做某事，那么将大有帮助。

temp = 
    Year    Jan Feb March   April   May ... Dec
0   2000... 50  50  60  70  80      ---      20
1   ...2020 50  50  60  70  80      ---      20



iterations = len(temp)
months = range(0,13)
for t in range(iterations):
    temp_row = temp.loc[t:t,'Jan':'Dec']
    display(temp_row)
    for k in temp_row:
        temp_curve = temp_row[k] 
        np.array(temp_curve)
        display(temp_curve)
        #plt.plot(months,temp_curve)

解决方法

这是我将对熊猫进行处理的示例代码。

{
  "rules": {
    ".read": "auth != null",".write": "auth != null","quotes": {
      ".indexOn": ["businessprofile_id","request_id"]
    },"quotes-by-business-profile": {
      ".indexOn": ["request_id"]
    },"businessprofiles": {
        "$userid":{
           ".indexOn": ["status"],".read": "auth.uid == $userid || auth.userId == $userid",".write": "auth.uid == $userid || auth.userId == $userid"
        
          }   
    },"requests": {
        "$requestid":{
            ".indexOn": ["userid","category","status"]
        },".indexOn": ["userid","status","accepted_businessprofile_id"]
    },"users" : {
        "$users" : {
          ".read": "auth.uid == $users || auth.userId == $users",".write": "auth.uid == $users || auth.userId == $users"
        }
      },"messages" : {
        ".indexOn" : ["request_id","businessprofile_userid","userid","businessprofile_id"]
      },"businesslocations" : {
        ".indexOn": "g"
      },"countries" :
      {
        ".read": true
      }
  }
}

对于您的情况，您需要将数据import pandas as pd import matplotlib.pyplot as plt # generate dummy date like yours temp = pd.DataFrame(np.random.rand(10,12)*30,columns=list('JFMAMJJASOND'),index=[2000,2001,2002,2003,2004,2005,2006,2007,2008,2009,20010]) for irow in temp.iterrows(): irow[1].plot(label=str(irow[0])) plt.legend(loc='best') 保存到年，然后您才能关注该帖子。

这是我的虚拟数据的样子。 打印（温度）

set_index