有没有一种方法可以使用通配符属性来过滤对象数组？

如何解决有没有一种方法可以使用通配符属性来过滤对象数组？

给出以下内容：

const cars = [
   {
      make: 'BMW',model: 'E46',year: 2002,},{
      make: 'Toyota',model: 'Altis',year: 2009,{
      make: 'Chevrolet',model: 'Camaro',year: 1969,model: 'Silverado',];

const filters = [
   {
      type: 'make',payload: 'Chevrolet',{
      type: 'year',payload: 2002,];

如何filter cars使用类似下面的代码？

let filteredCars = [];

filters.forEach(filter => filteredCars = cars.filter(car => car.[filter.type] === car.[filter.payload]));

解决方法

使用filter和some来匹配任何过滤器

cars.filter((o) => filters.some((f) => o[f.type] == f.payload))

const cars = [ { make: "BMW",model: "E46",year: 2002 },{ make: "Toyota",model: "Altis",year: 2009 },{ make: "Chevrolet",model: "Camaro",year: 1969 },model: "Silverado",];
const filters = [ { type: "make",payload: "Chevrolet" },{ type: "year",payload: 2002 },];

res = cars.filter((o) => filters.some((f) => o[f.type] == f.payload));
console.log(res);

或使用filter和every来匹配所有个过滤器

res = cars.filter((o) => filters.every((f) => o[f.type] == f.payload));

const cars = [ { make: "BMW",];

let res = cars.filter((o) => filters.every((f) => o[f.type] == f.payload));
console.log(res);

,

首先，编写一个使单个汽车与单个过滤器匹配的谓词。

function carMatchesFilter(car,filter) {
  return car[filter.type] === filter.payload;
}

如果我们想包括与所有过滤器匹配的汽车，我们将编写

const filteredCars = cars.filter(car =>
  filters.every(filter => carMatchesFilter(car,filter))
);

如果我们要包含与任何个过滤器匹配的汽车，则可以编写

const filteredCars = cars.filter(car =>
  filters.some(filter => carMatchesFilter(car,filter))
);

,

我认为使用lodash函数会很容易。

filteredCards = cars;
filters.forEach(function(element) {
    filteredCards = _.filter(filteredCards,function(o) {
        return o[element.type] == element.payload;
    });
});

我希望这会有所帮助。