一列的Y轴x不同列的Y轴到不同的子图

如何解决一列的Y轴x不同列的Y轴到不同的子图

嗨，我有一个数据框喜欢这个：

data1 = {"x": [10,20,30,40,50],"y": [0.01,0.02,0.03,0.04,0.05],"z": [0.11,0.12,0.13,0.14,0.15],"q": [0.21,0.22,0.23,0.24,0.25],}
df1 = pd.DataFrame (data1,columns = ['x','y','z','q'])

我想创建x相对于y，z以及相对于q的图，作为图上的子图。

我已经做到了，但是它们在同一个情节中

import matplotlib.pyplot as plt

plt.plot(df1['y'],df1['x'])
plt.plot(df1['z'],df1['x'])
plt.plot(df1['q'],df1['x'])

还有一种方法可以为eahc行添加标签吗？

解决方法

要向每行添加图例，可以在每行上添加标签，然后调用plt.legend()绘制图例。

import pandas as pd
import matplotlib.pyplot as plt

data1 = {"x": [10,20,30,40,50],"y": [0.01,0.02,0.03,0.04,0.05],"z": [0.11,0.12,0.13,0.14,0.15],"q": [0.21,0.22,0.23,0.24,0.25],}
df1 = pd.DataFrame (data1,columns = ['x','y','z','q'])

plt.plot(df1['y'],df1['x'],label='y')
plt.plot(df1['z'],label='z')
plt.plot(df1['q'],label='q')

plt.legend()

plt.show()

要在不同的子图上绘制它们，可以通过在nrows中定义ncols和plt.subplots()参数来创建mxn子图。然后在每个轴对象上绘制数据。

import pandas as pd
import matplotlib.pyplot as plt

data1 = {"x": [10,'q'])

figure,axs = plt.subplots(nrows=1,ncols=3,figsize=(8,4))

axs[0].plot(df1['y'],label='y')
axs[1].plot(df1['z'],label='z')
axs[2].plot(df1['q'],label='q')

axs[0].set_title('x against y')
axs[1].set_title('x against z')
axs[2].set_title('x against q')

plt.show()