PHP将数据从3个表关系循环到每个div元素

如何解决PHP将数据从3个表关系循环到每个div元素

我需要帮助。 我想从3种表格关系中在Codeigniter PHP页面中显示div元素：

my Table is=

    Category =>category_id,category_name 
    Sub_Category => sub_category_id,category_id,sub_category_name  
    Item => item_id,sub_category_id,item_name

模型=

public function item_data()
   {
   $query = $this->db->query('SELECT A.item_name,B.sub_category_name,C.category_name FROM 
   item A
   sub_kategori A 
   LEFT JOIN sub_category B ON B.sub_category_id = A.sub_category_id
   LEFT JOIN category C ON C.category_id = B.category_id
   ');
   return $query->result();
   }

控制器：

function item_view()
{
//--------
$item_data = $this->model_app->data_ticket();
$data['item_data'] = $item_data;

$this->load->view('template',$data);
}

查看：

<?php $no = 0; foreach($item_data as $row) : $no++;?>
 <div class="card">           
   <div class="card-header">
     <h3 class=""><?php echo $row->sub_category_name;?></h3>
     <h5 class=""><?php echo $row->category_name;?></h5>
   </div>
   <div class="card-footer">
     <ul>

//... How to show/Looping item_name by sub_category_id ...?

       <li class="nav-item">
         <a href="#" class="nav-link">
           <?php echo $row->item_name;?>
         </a>
       </li>                                          
     </ul>
   </div>
 </div>
<?php endforeach;?>

上面的代码按item_name显示重复的sub_category_name。 输出Now =

sub_category1 => category1=>item1
sub_category1 => category1=>item2
sub_category1 => category1=>item3

sub_category2 => category1=>item4
sub_category2 => category1=>item5
sub_category2 => category1=>item6
...

我想获得实现数据回显=

sub_category1 => category1=>item1,item2,item3
sub_category2 => category1=>item4,item5,item6
.....

问题： 如何通过sub_category_id ...显示/显示每个item_name？

感谢您的帮助。

解决方法

我假设您的查询结果如下：

Iphone Xr 64 GB|Iphone|Apple

Iphone XS 128 GB|Iphone|Apple

Airpod 2| Headphone|Apple

Airpod Pro| Headphone|Apple

Macbook air 2020 128Gb| laptop|Apple

因此，如果要按子类别显示组，则应在模型或控制器中重组数据，并且不要在视图中进行，因为嵌套php代码和html代码很难调试和重用。像这样的结构：

[Note]：因为查询的输出是stdclass，所以在使用我的代码之前让我们将其转换为数组：

$arr = json_decode(json_encode($yourObject),TRUE);

['Iphone'=>
    [
        'category'=>'Apple','items'=> ['Iphone Xr 64 GB','Iphone XS 128 GB']
    ]
]

我有一些代码可以让您按sub_category分组列表

$arr = [
    ['category'=>'Apple','sub_category'=>'Iphone','item'=>'Iphone XR'],['category'=>'Apple','item'=>'Iphone XS'],'item'=>'Iphone X'],'sub_category'=>'HeadPhone','item'=>'AirPod 2'],'sub_category'=>'Laptop','item'=>'Macbook air'],['category'=>'Samsung','sub_category'=>'MobilePhone','item'=>'Galaxy S10'],];
$newArr = [];
foreach ($arr as $key => $item) {
    $newArr[$item['sub_category']][$key] = $item;
}

结果将是：

$newArr = [
    'Iphone'=>[
        ['category'=>'Apple',],...
];

视图应为：

<?php foreach($new_arr as $key => $value)?>
 <div class="card">           
   <div class="card-header">
     <h3 class=""><?php echo $key;?></h3>
     <h5 class=""><?php echo $value[0]['category'];?></h5>
   </div>
   <div class="card-footer">
     <ul>
       <?php foreach($value as $item) ?>
          <li class="nav-item">
             <a href="#" class="nav-link">
           <?php echo $item['item']?>
         </a>
       </li> 
       <?php endforeach;?>                                         
     </ul>
   </div>
 </div>
<?php endforeach;?>