从具有名字，姓氏和WHERE子句的现有工作表值中查询需要匹配名字和姓氏

如何解决从具有名字，姓氏和WHERE子句的现有工作表值中查询需要匹配名字和姓氏

我希望使用where子句中的现有数据来获取查询结果。现有的要查询的数据和表将名字和姓氏分为两个字段。我需要一种在数组和单个where条件中传递两个字段的方法。

例如，这是我需要查询的源数据的工作表：

Dob         Last        First     SSN
6/6/2006    Notaperson  Billy     999880006
1/1/2001    Testing     Marco     999880001/217061866
2/2/2002    Case        Delilah   999880002
3/3/2003    Testcase    Julius    999880003
4/4/2004    Notreal     Adrianna  999880004
5/5/2005    Fake        Julianna  999880005
12/1/2017   Mars        Danielle  999880005

Image of source data worksheet

我需要查询任何Dob，任何SSN和任何MATCHING的姓氏和名字。 例如： 返回所有行，其中Dob = 6/6/2006且ssn = 999880006和FIRST / LAST = Notaperson Billy

下面是我写的内容，但是它返回的是last = Notaperson的任何行和/或带有first = Billy的任何行。

如何设置where子句以将名字和姓氏作为单个数据值进行搜索？

'''

with subjects as (
Select 
    s.subject_key,s.dob,n.last,n.first,sa_cid.alias                      as cid,sa_cid.facility_key               as cid_facility_key,sa_cid.primary_aliaås             as cid_primary_alias,sa_cid.subject_alias_type_key     as cid_subject_alias_type_key,sa.alias,sa.facility_key,sa.primary_alias,sa.subject_alias_type_key
from subject s

inner join subject_alias sa_cid
    on sa_cid.subject_key = s.subject_key
        and sa_cid.subject_alias_type_key = 3

inner join subject_alias sa
    on sa.subject_key = s.subject_key
        and sa.subject_alias_type_key != 3      

inner join name n
    on n.name_key = s.current_name_key

WHERE 1 = 1
    and dob = ANY(
        '{6/6/2006,1/1/2001,2/2/2002,3/3/2003,4/4/2004,5/5/2005,12/1/2017}')
    or (
                n.last = ANY(
                '{NOTAPERSON,TESTING,CASE,TESTCASE,NOTREAL,FAKE,MARS
                }')     
                OR n.first = ANY(
                '{BILLY,MARCO,DELILAH,JULIUS,ADRIANNA,JULIANNA,DANIELLE
                }')
            )
    or sa.alias = any('{
        999880006,999880001/217061866,999880002,999880003,999880004,999880005,999880005}')
)

select 
    subject_key,dob,last,first,cid,array_agg(alias || ':' || facility_key || ':' || subject_alias_type_key) as other_alias
from subjects 
group by subject_key,cid
order by cid,first

'''

解决方法

只需选择您的输入，然后跳过所有联接，因为我们没有其他表的输入。 你的意思是这样吗？您可以将行表达式放入IN()列表中...

请注意，ANY('{}')表达式绝不是典型的SQL语法，而用于指定一组值（或实际上是行）的IN()表示法是

。

WITH
input(dob,last,first,ssn) AS (
          SELECT DATE '6/6/2006','Notaperson','Billy','999880006'           
UNION ALL SELECT DATE '1/1/2001','Testing','Marco','999880001/217061866'
UNION ALL SELECT DATE '2/2/2002','Case','Delilah','999880002'
UNION ALL SELECT DATE '3/3/2003','Testcase','Julius','999880003'
UNION ALL SELECT DATE '4/4/2004','Notreal','Adrianna','999880004'
UNION ALL SELECT DATE '5/5/2005','Fake','Julianna','999880005'
UNION ALL SELECT DATE '12/1/2017','Mars','Danielle','999880005'
)
SELECT
  *
FROM input
WHERE dob IN (
  DATE '6/6/2006',DATE '1/1/2001',DATE '2/2/2002',DATE '3/3/2003',DATE '4/4/2004',DATE '5/5/2005',DATE '12/1/2017'
)
  OR (last,first) IN (
     ('Notaperson','Billy'   ),('Testing','Marco'   ),('Case','Delilah' ),('Testcase','Julius'  ),('Notreal','Adrianna'),('Fake','Julianna'),('Mars','Danielle')
)
-- out     dob     |    last    |  first   |         ssn        
-- out ------------+------------+----------+--------------------
-- out  2006-06-06 | Notaperson | Billy    | 999880006
-- out  2001-01-01 | Testing    | Marco    | 999880001/217061866
-- out  2002-02-02 | Case       | Delilah  | 999880002
-- out  2003-03-03 | Testcase   | Julius   | 999880003
-- out  2004-04-04 | Notreal    | Adrianna | 999880004
-- out  2005-05-05 | Fake       | Julianna | 999880005
-- out  2017-12-01 | Mars       | Danielle | 999880005