如何仅打印或获取第二个结果

如何解决如何仅打印或获取第二个结果

我只想获取第二个结果，num打印并使用它。

savee1是一个.txt文件

def copycoordinates():


savee1 = filedialog.askopenfilename(initialdir="C:/USERS/" + username + "/documents/Euro Truck Simulator 2/profiles",title="Choose FIRST File",filetypes=[("sii files","*.sii")])

savee2 = filedialog.askopenfilename(initialdir="C:/USERS/" + username + "/documents/Euro Truck Simulator 2/profiles",title="Choose SECOND File","*.sii")])

i1 = Label(frame5,text="Chosen FIRST File \n" + savee1)
i1.pack()

i2 = Label(frame5,text="Chosen SECOND File \n" + savee2)
i2.pack()

command=lambda:[save1()]
subprocess.Popen(["C:/SII_Decrypt.exe",savee1])

command=lambda:[save2()]
subprocess.Popen(["C:/SII_Decrypt.exe",savee2])

#time.sleep(1)

with open(savee1,"r+") as save1:

    for num,line in enumerate(save1,1):
        if "truck_placement:" in line:
            print(num)
            

解决方法

results = list()
with open(savee1,"r+") as save1:

for num,line in enumerate(save1,1):
    if "truck_placement:" in line:
        print(num)
        results.append(num)
print(results[1]) #this is the value you want

,

不确定文本文件中的内容，但是通常情况是以某种方式分隔的（换行符，制表符分隔，逗号分隔）。您应该对分隔的内容进行拆分，然后可以对结果列表进行索引。以下代码假定您想要的东西用换行符分隔：

with open(save1,"r+") as infile:
    f=infile.read()

list_o_txt = f.split('\n')
print (list_o_txt[1])

如果要创建仅包含短语“ truck_placement”的文本的子列表

with open(save1,'r') as infile:
    f=infile.read()

list_o_txt = f.split('\n') # produces a list
filtered_list = [line for line in list_o_txt if 'truck_placement' in line] #filters the list
print (filtered_list[1]) #prints the second item

,

如果您想参加第二场比赛，可以尝试：

with open(savee1,"r+") as save1:

match = 0
for num,1):
    if 'truck_placement:' in line:
        match += 1
        if match == 2
            print(num)
        else:
            continue

该数字将在第二个匹配项上显示。

肯定有更好的方法，但这是最简单的解决方案之一。