如何解决为什么这些代码行会导致键盘滞后,还有替代方法吗?
因此,我正在学习python,并试图创建一个代码来检测Minecraft中某些东西在按下“空格”和“ a”之间的时间。问题在于该程序滞后了我的键盘/导致键盘按下延迟。
我已将问题缩小为:
while True:
if keyboard.is_pressed ('p'):
strafe45()
如果我将其替换为以下内容:它不会导致键盘延迟。
run = 1
while run == 1:
strafe45()
我认为是因为第一个是不断检查我是否键入'p',这是造成延迟的原因,但是我还能怎么写类似的东西?我无法在run == 1时使用,因为最终会出现错误,因为我按住'a'并且变量'start'不再具有分配的值。
如果需要,这里是完整的代码:
import keyboard
import time
import math
def strafe45():
while True:
if keyboard.is_pressed ('space'):
print ("starting timer")
start = time.perf_counter()
time.sleep(0.05)
if keyboard.is_pressed ('a'):
end = time.perf_counter()
print ("ending timer")
tickTime = end - start
tick = 0.05
if tickTime > tick:
print ("Did not make strafe. Too slow by " + str(tickTime - tick) + "\n" +
"Time passed (r): " + str(round(tickTime/tick,2)) + "\n" +
"Time passed (a): " + str(tickTime/tick))
break
if tickTime < tick:
print ("Did make strafe by " + str(tick - tickTime) + "\n" +
"Time passed (r): " + str(round(tickTime/tick,2)) + "\n" +
"Time passed (a): " + str(tickTime/tick))
break
run = 1
while run == 1:
strafe45()
"""while True:
if keyboard.is_pressed ('p'):
strafe45()"""
解决方法
添加一个钩子并仅在按下某个键时进行检查,而不是经常检查每个循环。 keyboard.on_press(callback)
向每个调用给定回调的键盘和键添加一个侦听器。这样可以缓解您的延迟问题。查看Keyboard API Page以获得完整的文档
def check_key(x): #x should be an keyboard.KeyboardEvent
print x.name,x.scan_code,x.time
if x.name == "":
something
elif x.name == "":
something else
keyboard.on_press(check_key)
,
while True:
if keyboard.is_pressed ('p'):
strafe45()
按下p
键时,将呼叫strafe45
,结果发生了一些sleep
呼叫。
只要没有按下p
键,就会出现紧密的while循环,不断检查何时按下键。
您应该有一个单个 while
循环,在键处理函数的 outside 外,并确保每次time.sleep
调用都通过此循环-通过将其显式放入循环中。如果您调用用于处理键的函数(随着代码变得更加复杂,这是一个好主意),则它们不应具有自己的循环-它们应根据所按的内容对程序状态进行适当的更改。
例如:
begin = None
def begin_timing():
global begin
begin = time.perf_counter()
def end_timing():
global begin
if begin is not None: # otherwise,we weren't timing yet.
end = time.perf_counter()
print('elapsed time:',end - begin)
begin = None # so that we can begin timing again.
while True:
# There needs to be a delay each time through the loop,# but it needs to be considerably shorter than the time interval you're
# trying to measure.
time.sleep(0.01)
if keyboard.is_pressed('b'): # begin
begin_timing()
elif keyboard.is_pressed('e'): # end
end_timing()
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