如何解决使用vuejs获取树的特定节点的详细信息
我有一个树数据结构。在该结构中,存在具有文件数组的嵌套子节点。我想根据节点单击事件获取这些文件的详细信息。
这是树的模拟数据:
data:[{
id: 1,name: 'Resources',type:'folder,files: [],children: [
{
id: 4,name: 'Resources Zone 1-A',type: 'folder',files: [
"Resources-zone-east.doc","Resources-zone-east-1-A.doc"
]
}
]
},{
id: 2,name: 'Services',files: [
"Services-east-zone-2A.doc","Services-West-zone-2A.doc"
],children: [
id: 5,name: 'Services-South-Zone-3B",files: [
"Services-South-zone-3B1.doc","Services-South-zone-3B2.doc"
],]
},{
id: 3,name: 'Servers',files: [
'Servers-east-zone-3B.doc','Servers-west-zone-3B.doc'
],children: []
}]
我想这样做。如果我单击子节点'Services-South-Zone-3B',那么我会将这些文件放入数组->
let result=["Services-South-zone-3B1.doc","Services-South-zone-3B2.doc"]
如何像这样迭代和显示文件?
解决方法
您可以使用递归组件,请参见:https://vuejs.org/v2/guide/components-edge-cases.html#Recursive-Components
这是一个基于您的数据的简单示例:
const Node = {
name: 'node',template: `
<div>
<a @click="$emit('input',value.files)">
{{ value.name }}
</a>
<node v-if="value.children" v-for="child in value.children" :key="child.id" :value="child" @input="$emit('input',$event)"/>
</div>
`,props: ['value']
};
new Vue({
el: '#app',components: {
Node
},data() {
return {
tree: {
id: 0,name: 'Root',files: [],children: [{
id: 1,name: 'Resources',type: 'folder',children: [{
id: 4,name: 'Resources Zone 1-A',files: [
'Resources-zone-east.doc','Resources-zone-east-1-A.doc'
]
}]
},{
id: 2,name: 'Services',files: [
'Services-east-zone-2A.doc','Services-West-zone-2A.doc'
],children: [{
id: 5,name: 'Services-South-Zone-3B',files: [
'Services-South-zone-3B1.doc','Services-South-zone-3B2.doc'
]
}]
},{
id: 3,name: 'Servers',files: [
'Servers-east-zone-3B.doc','Servers-west-zone-3B.doc'
],children: []
}
]
}
};
},methods: {
log(value) {
console.log(value);
}
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/vue/2.5.17/vue.js"></script>
<div id="app">
<node :value="tree" @input="log"></node>
</div>
这是基本的树结构。 node
组件引用自己对其子对象进行迭代。 input
事件冒泡到根实例。
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。