如何解决Django详细视图:在详细视图中从另一个模型检索数据
我试图显示与给定“项目”相关的“ cliqueclasses”列表,但只是无法正确获取循环模板。我也想更进一步,只附加与该项目相关的类(基于外键)
我已经尝试了一段时间,到目前为止还没有碰到任何运气,尤其是在模板方面!
Models.py
class Item(models.Model):
title = models.CharField(max_length=100)
price = models.FloatField()
discount_price = models.FloatField(blank=True,null=True)
category = models.CharField(choices=CATEGORY_CHOICES,max_length=2)
label = models.CharField(choices=LABEL_CHOICES,max_length=1)
slug = models.SlugField()
description = models.TextField()
image = models.ImageField()
def save(self,*args,**kwargs):
...
def __str__(self):
return self.title
...
class CliqueClass(models.Model):
title = models.CharField(max_length=100)
start_date = models.DateTimeField(auto_now_add=True)
end_date = models.DateTimeField(auto_now_add=True)
item = models.ForeignKey(Item,related_name='items',on_delete=models.CASCADE)
description = models.TextField()
plan = models.TextField()
slug = models.SlugField()
image = models.ImageField()
def save(self,**kwargs):
...
def __str__(self):
...
我的Views.py
class ItemDetailView(DetailView):
model = Item
template_name = "clique.html"
# queryset = CliqueClass.objects.filter(title=Item.title)
def get_context_data(self,**kwargs):
"""
This has been overridden to add `cliqueclass` to the template context,now you can use {{ cliqueclass }} within the template
"""
context = super().get_context_data(**kwargs)
context['cliqueclass'] = CliqueClass.objects.all()
return context
我的网址是.py
path('clique/<slug>/',ItemDetailView.as_view(),name='clique'),
我的clique.html模板:
{% for class in object.cliqueclass_set.all %}
<!--Look through all cliques classes-->
<div class="mb-3">
<a href="">
<span>{{ class }}</span>
<span class="badge purple mr-1">{{ class.title }}</span>
<p>Lorem ipsum dolor sit amet consectetur adipisicing elit. Natus suscipit modi sapiente illo soluta odit
voluptates,quibusdam officia. Neque quibusdam quas a quis porro? Molestias illo neque eum in laborum.</p>
</a>
</div>
<hr class="solid">
{% endfor %}
任何帮助将不胜感激:)
解决方法
首先,您需要更改FK的 related_name
class CliqueClass(models.Model):
# rest of your code
item = models.ForeignKey(Item,related_name='clique_classes',
on_delete=models.CASCADE)
related_name
可以是任意名称,但是,我认为clique_classes
是更合适的名称。
如果您不熟悉related_name
,请阅读更多
更改related_name
后,您需要通过执行以下命令来迁移数据库,
-
python manage.py makemigrations
-
python manage.py migrate
然后,在您看来,删除 get_context_data(...)
方法,因为它与此特定问题无关。
class ItemDetailView(DetailView):
model = Item
template_name = "clique.html"
然后,将模板代码更改为
{% for clique_class in object.clique_classes.all %}
{{ clique_class.title }}
{% endfor %}
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