Python：如何从字典中获取最高的键，一旦找到键/值，该键又如何？

如何解决Python：如何从字典中获取最高的键，一旦找到键/值，该键又如何？

嘿，我有字典显示：

Shows = {177.17: ['SELECT * FROM `breaking.bad` '],190.16: ['SELECT * FROM `breaking.bad`'],81.72: ['SELECT * FROM `mad.men`'],74.36: ['SELECT * FROM `game.of.thrones`'],74.37: ['SELECT * FROM `game.of.thrones`']}

如果这些键值出现，这里有一个我要匹配的列表：

list = ['breaking.bad','mad.men','game.of.thrones','the.mandalorian']

当前我要实现的是，一旦列表值与字典中的列表匹配，我将获得这些键的最高值及其值。

到目前为止，我所做的是：

for key,value in Shows.items():
    for lst in list:
        if lst in value and 'breaking.bad' in value and max(key) :
            print(lst)

有什么想法可以帮助我实现目标吗？

解决方法

不是最有效的方法，而是先循环“表”，然后为每个节目获取字典并找到最大值

shows = {177.17: ['SELECT * FROM `breaking.bad` '],190.16: ['SELECT * FROM `breaking.bad`'],81.72: ['SELECT * FROM `mad.men`'],74.36: ['SELECT * FROM `game.of.thrones`'],74.37: ['SELECT * FROM `game.of.thrones`']}
tables = ['breaking.bad','mad.men','game.of.thrones','the.mandalorian']


for table in tables:  # don't name variables as list
    sub_shows = {key:value for key,value in shows.items() if any(table in v for v in value)}
    if sub_shows:  # max throws error if list is empty
        print(max(sub_shows),table)

输出

190.16 breaking.bad
81.72 mad.men
74.37 game.of.thrones

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我质疑仅列出一项的用例，或者为什么在词典中需要SQL查询