python中的Lambda函数返回配置错误

如何解决python中的Lambda函数返回配置错误

我一直从Lambda函数中收到此错误消息：

Tue Aug 18 21:15:31 UTC 2020 : Execution failed due to configuration error: Malformed Lambda proxy response
Tue Aug 18 21:15:31 UTC 2020 : Method completed with status: 502

我要做什么是让用户输入两个数字。 lambda函数接受这些数字，然后通过引用列表的函数运行它们。输出是列表中的一行，其中包含两个数字，一个名称和一个默认消息。 我的Lambda函数在Python 3.6中，并且我正在通过GET方法使用API​​网关。 List_r5是一个带有少量列表的python脚本：

import json
from math import cos,asin,sqrt
import List_r5

print('Loading function')

#Parse out query string parameters
def lambda_handler(event,context):
    usera_in = event['queryStringParameters']['usera_in']
    userb_in = event['queryStringParameters']['userb_in']

    print('UserA_In=' + usera_in)
    print('UserB_In=' + userb_in)

#Define the function
def dis(us1,ub1,us2,ub2):
    p = 0.017453292519943295
    a = 0.5 - cos((us2-us1)*p)/2 + cos(us1*p)*cos(us2*p) * (1-cos((ub2-ub1)*p)) / 2
    return 12742 * asin(sqrt(a))

def clo(database,input):
    return min(database,key=lambda p: dis(v['us'],v['ub'],p['us'],p['ub']))

    coord = {'us': usera_in,'ub': userb_in}   
    output = clo(List_r5.data,coord)

    sta_output = output['NAME']
    us_output = output['us']
    ub_output = output['ub']

#Body of response object
    gResponse = {}
    gResponse['Sta'] = sta_output
    gResponse['UserA'] = us_output
    gResponse['UserB'] = ub_output
    gResponse['Message'] = 'All good on your end?'


#HTTP response object
    responseObject = {}
    responseObject['statusCode'] = 200
    responseObject['headers'] = {}
    responseObject['headers']['Content-Type'] = 'application/json'
    responseObject['body'] = json.dumps(gResponse)

#Return response object
    return responseObject

解决方法

def clo. . .之后到代码段末尾的所有内容都在clo函数定义内，因此它将永远不会执行。取消缩进代码

def clo(database,input):
    return min(database,key=lambda p: dis(v['us'],v['ub'],p['us'],p['ub']))

coord = {'us': usera_in,'ub': userb_in}   
output = clo(List_r5.data,coord)

sta_output = output['NAME']
us_output = output['us']
ub_output = output['ub']

#Body of response object
gResponse = {}
gResponse['Sta'] = sta_output
gResponse['UserA'] = us_output
gResponse['UserB'] = ub_output
gResponse['Message'] = 'All good on your end?'


#HTTP response object
responseObject = {}
responseObject['statusCode'] = 200
responseObject['headers'] = {}
responseObject['headers']['Content-Type'] = 'application/json'
responseObject['body'] = json.dumps(gResponse)

#Return response object
return responseObject

,

在我看来，这是一个压痕问题。尝试缩进函数dis（）和clo（）及其内容。

import json
from math import cos,asin,sqrt
import List_r5

print('Loading function')

#Parse out query string parameters
def lambda_handler(event,context):
    usera_in = event['queryStringParameters']['usera_in']
    userb_in = event['queryStringParameters']['userb_in']

    print('UserA_In=' + usera_in)
    print('UserB_In=' + userb_in)

    #Define the function
    def dis(us1,ub1,us2,ub2):
        p = 0.017453292519943295
        a = 0.5 - cos((us2-us1)*p)/2 + cos(us1*p)*cos(us2*p) * (1-cos((ub2-ub1)*p)) / 2
        return 12742 * asin(sqrt(a))

    def clo(database,input):
        return min(database,p['ub']))

    coord = {'us': usera_in,'ub': userb_in}   
    output = clo(List_r5.data,coord)

    sta_output = output['NAME']
    us_output = output['us']
    ub_output = output['ub']

#Body of response object
    gResponse = {}
    gResponse['Sta'] = sta_output
    gResponse['UserA'] = us_output
    gResponse['UserB'] = ub_output
    gResponse['Message'] = 'All good on your end?'


#HTTP response object
    responseObject = {}
    responseObject['statusCode'] = 200
    responseObject['headers'] = {}
    responseObject['headers']['Content-Type'] = 'application/json'
    responseObject['body'] = json.dumps(gResponse)

#Return response object
    return responseObject