使用python和pygame在游戏板上创建游戏部件并将其放置

如何解决使用python和pygame在游戏板上创建游戏部件并将其放置

我只是一个初学者。我决定使用pygame制作棋盘游戏。我使用以下代码创建了开发板：

import pygame
import sys


pygame.init()
#define colour
white = (255,255,255)
black = (0,0)

red = (255,0)
green = (0,0)
blue = (0,255)
yellow= (255,0)



#opening window
screen = pygame.display.set_mode((800,600))

pygame.draw.rect(screen,red,(200,100,250,250),2)
pygame.draw.rect(screen,green,(150,75,350,300),(100,50,450,350),2)
#draw lines
#upper line
pygame.draw.line(screen,white,(325,50),100),3)
#lower line
pygame.draw.line(screen,400),3)
#left line
pygame.draw.line(screen,200),3)
#right line
pygame.draw.line(screen,(450,(550,3)

#updateing window
while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()

    pygame.display.update()

现在，我想添加两个具有两种不同颜色的游戏作品，在每个角和线的交点处分别为黑色和红色。我该怎么办？

解决方法

每当您发现自己重复使用数字块重复行时，例如您对矩形函数的调用-考虑一下如何将数字存储在某种列表，元组或数据结构中可以简化代码。

例如：

pygame.draw.rect(screen,red,(200,100,250,250),2)
pygame.draw.rect(screen,green,(150,75,350,300),(100,50,450,350),2)

可能会变成：

board_rects = [  ( 200,red ),( 150,300,green ),( 100,red ) ]
for rect in board_rects:
    x_pos,y_pos  = rect[0],rect[1]
    width,height = rect[2],rect[3]
    colour        = rect[4]
    pygame.draw.rect( screen,colour,( x_pos,y_pos,width,height ),2 )

这显然是更多的代码，但是它更简单，因为只有一个调用可以绘制所有矩形。如果说，矩形的数量随难度级别的增加而增加，仅需向board-rects添加另一个数据元组，就没有逻辑上的改变。

类似地：

board_lines = [ ( 325,325,100 ),( 325,400 ),200,200 ),( 450,550,200 ) ]
for line in board_lines:
    line_from = ( line[0],line[1] )
    line_to   = ( line[2],line[3] )
    pygame.draw.line( screen,white,line_from,line_to,3 )

现在，板的矩形和直线都存储在数据结构中。因此，可以遍历列表执行其他测试和操作。 现在我们有了数据结构中的所有点和线，我们可以在它们上进行交叉点测试：

for line in board_lines:
    for rect in board_rects:
        rect = rect[ 0: -1 ] # trim off the colour
        intersection_points = lineRectIntersectionPoints( line,rect )
        for p in intersection_points:
            pygame.draw.circle( screen,blue,p,10 )  # Draw a circle at the point

newer version of rename

确定线与矩形的交点的一种方法是将矩形视为4条线的集合，并分别确定给定线的。当然，如果线是平行的，它们不会相交（它们确实会相交，但是无限地），因此我们也必须检查一下。最后，我们不在乎线是否在屏幕外相交，这也被认为是不相交的。

这给了我们令人讨厌的交集功能，但实际上只是一堆简单的几何计算相互关联：

def lineRectIntersectionPoints( line,rect ):
    """ Get the list of points where the line and rect
        intersect,The result may be zero,one or two points.

        BUG: This function fails when the line and the side
             of the rectangle overlap """

    def linesAreParallel( x1,y1,x2,y2,x3,y3,x4,y4 ):
        """ Return True if the given lines (x1,y1)-(x2,y2) and
            (x3,y3)-(x4,y4) are parallel """
        return (((x1-x2)*(y3-y4)) - ((y1-y2)*(x3-x4)) == 0)

    def intersectionPoint( x1,y4 ):
        """ Return the point where the lines through (x1,y2)
            and (x3,y4) cross.  This may not be on-screen  """
        #Use determinant method,as per
        #Ref: https://en.wikipedia.org/wiki/Line%E2%80%93line_intersection
        Px = ((((x1*y2)-(y1*x2))*(x3 - x4)) - ((x1-x2)*((x3*y4)-(y3*x4)))) / (((x1-x2)*(y3-y4)) - ((y1-y2)*(x3-x4)))
        Py = ((((x1*y2)-(y1*x2))*(y3 - y4)) - ((y1-y2)*((x3*y4)-(y3*x4)))) / (((x1-x2)*(y3-y4)) - ((y1-y2)*(x3-x4)))
        return Px,Py

    ### Begin the intersection tests
    result = []                                 # empty list for result-set
    line_x1,line_y1,line_x2,line_y2 = line   # split into components
    pos_x,pos_y,height = rect

    ### Convert the rectangle into 4 lines
    rect_lines = [ ( pos_x,pos_x+width,pos_y ),( pos_x,pos_y+height,pos_y+height ),# top & bottom
                   ( pos_x,pos_x,( pos_x+width,pos_y+height ) ] # left & right

    ### intersect each rect-side with the given line
    for r in rect_lines:
        rx1,ry1,rx2,ry2 = r
        if ( not linesAreParallel( line_x1,line_y2,rx1,ry2 ) ):    # not parallel
            pX,pY = intersectionPoint( line_x1,ry2 )  # so intersecting somewhere
            # Lines intersect,but is it on-screen?
            if ( pX >= 0 and pY >= 0 and pX < WINDOW_WIDTH and pY < WINDOW_HEIGHT ):          # yes! on-screen
                result.append( ( round(pX),round(pY) ) )                                     # keep it
                if ( len( result ) == 2 ):
                    break   # Once we've found 2 intersection points,that's it

    return result

将它们放在一起：

import pygame
import sys

WINDOW_WIDTH = 800
WINDOW_HEIGHT= 600

#define colour
white = (255,255,255)
black = (0,0)

red = (255,0)
green = (0,0)
blue = (121,202,255)
yellow= (255,0)


def lineRectIntersectionPoints( line,Py

    ### Begin the intersection tests
    result = []
    line_x1,pos_y+height ) ] # left & right

    ### intersect each rect-side with the line
    for r in rect_lines:
        rx1,that's it

    return result



#opening window
pygame.init()
screen = pygame.display.set_mode((WINDOW_WIDTH,WINDOW_HEIGHT))

#pygame.draw.rect(screen,2)
#pygame.draw.rect(screen,2)
##draw lines
##upper line
#pygame.draw.line(screen,(325,50),100),3)
##lower line
#pygame.draw.line(screen,400),3)
##left line
#pygame.draw.line(screen,200),3)
##right line
#pygame.draw.line(screen,(450,(550,3)

board_rects = [  ( 200,2 )

board_lines = [ ( 325,3)    

for line in board_lines:
    for rect in board_rects:
        rect = rect[ 0: -1 ] # trim off the colour
        intersection_points = lineRectIntersectionPoints( line,10 )  # Draw a circle at the intersection point

#updateing window
while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()

    pygame.display.update()