根据条件将文本附加到html文档中的组

如何解决根据条件将文本附加到html文档中的组

我正在解析一个大型{% extends 'base.html' %} {% load crispy_forms_tags %} {% block page_head %}Add Product{% endblock %} {% block navbar %} <navbar class="mr-auto"> <div class="container-fluid"> <ul class="nav navbar-expand"> <li> <button type="submit" form="p-form" class="btn btn-outline-secondary">Add Product</button> <button class="btn btn-outline-secondary" onclick="document.location='{% url 'prodlist' %}'">Close Without Saving</button> </li> </ul> </div> </navbar> {% endblock %} {% block content %} <form id="p-form" action="{% url 'newproduct' %}" method="post"> <!-- {{form.prod_code|as_crispy_field}} {{form.prod_descr|as_crispy_field}} {{form.supplier|as_crispy_field}} {{form.list_price|as_crispy_field}} {{form.category|as_crispy_field}} --> {% csrf_token %} <div class="container-fluid "> <div class="row"> <div class="col-6 "> <div class="row"> <div class="col-3">Product Code</div> <div class="col-8" >{{form.prod_code|as_crispy_field}}</div> <div class="col-1"></div> </div> <div class="row"> <div class="col-3">Prod Descr</div> <div class="col-8">{{form.prod_descr|as_crispy_field}}</div> <div class="col-1"></div> </div> <div class="row"> <div class="col-3">Supplier</div> <div class="col-8">{{form.supplier|as_crispy_field}}</div> <div class="col-1"></div> </div> </div> <div class="col-6 "> <div class="row "> <div class="col-4">List Price</div> <div class="col-8">{{form.list_price|as_crispy_field}}</div> </div> <div class="row"> <div class="col-4">Serialsed Item</div> <div class="col-8">{{form.serialsed_item|as_crispy_field}}</div> </div> <div class="row"> <div class="col-4">Category</div> <div class="col-8">{{form.category|as_crispy_field}}</div> </div> </div> </div> </div> </form> {% endblock content %} 文档。我已经使用html对文本进行“分组”并使用groups进行了分隔。整个文本位于文档的\n\n标记内。

每个组都有5个字段，<font> </font>

我需要使用每个“组”中的Serial#.........,Cust#...........,Customer Name...,BILL TO NO NAME.,DATE......，并将其与列表中的每个其他组进行比较，以查找重复的Cust#...........。

如果找到重复项，那么我需要将Cust#...........附加到每个组中，并将重复项BILL TO NO NAME.

示例html：

Cust#...........

我需要的输出是： Serial#......... 12345678974566321\nCust#........... 123456\nCustomer Name... Humpfrey Bear\nBILL TO NO NAME. Bill To: 001166 - Some Company\nDATE...... 01/01/00\n\n'Serial#......... sgfdsfd546545645\nCust#........... 123456\nCustomer Name... Humpfrey Bear\nBILL TO NO NAME. Bill To: 0165487 - Some Other Company\nDATE...... 01/01/00\n\n'Serial#......... Jgfdhdgfhgfdh4545\nCust#........... 88483\nCustomer Name... John Smith\nBILL TO NO NAME. Bill To: 0146897 - Some Company\nDATE...... 01/01/00\n\n'Serial#......... JF2SJads5dsafdsaf\nCust#........... 015648\nCustomer Name... Eric Cantona\nBILL TO NO NAME. Bill To: 8888154 - Man Utd\nDATE...... 01/01/00\n\n'Serial#......... JdsfrfdsgHG091797\nCust#........... 015648\nCustomer Name... Eric Cantona\nBILL TO NO NAME. Bill To: 9876524 - Big Big Company\nDATE...... 01/01/00\n\n'

我的输出省略了基于Cust＃...... xxxxx的重复项，但是我只是想让我的预期结果更清晰些。我可以稍后将重复项清理掉。

到目前为止，我剩余部分的缩略版是无关紧要的。

Serial#......... 12345678974566321\nCust#........... 123456\nCustomer Name... Humpfrey Bear\nBILL TO NO NAME. Bill To: 001166 - Some Company Bill To: 0165487 - Some Other Company\nDATE...... 01/01/00\n\n',Serial#......... JF2SJads5dsafdsaf\nCust#........... 015648\nCustomer Name... Eric Cantona\nBILL TO NO NAME. Bill To: 8888154 - Man Utd Bill To: 9876524 - Big Big Company\nDATE...... 01/01/00\n\n'

解决方法

这与您问题中的预期输出不完全相同，但可能会让您足够接近：

bills = """[your html above]"""
groups = bills.replace('Serial#','xxxSerial#').split('xxx')
cust_nums = []
ng= []
for group in groups[1:]:
    items = group.split('\n')
    cn = items[1].split('. ')[1]
    bill = items[3].split('. ')[1]
    if cn not in cust_nums:
        cust_nums.append(items[1].split('. ')[1])            
    else:
        items[3]+=' '+bill
        ng.append(items[:-2])
ng

输出：

[['Serial#......... sgfdsfd546545645','Cust#........... 123456','Customer Name... Humpfrey Bear','BILL TO NO NAME. Bill To: 0165487 - Some Other Company Bill To: 0165487 - Some Other Company','DATE...... 01/01/00'],['Serial#......... JdsfrfdsgHG091797','Cust#........... 015648','Customer Name... Eric Cantona','BILL TO NO NAME. Bill To: 9876524 - Big Big Company Bill To: 9876524 - Big Big Company','DATE...... 01/01/00']]

,

如果您的目标是识别重复的Cust#值，则这是一种方法：

import re

sep = "Serial#"

def get_cust_number(entry):
    """ Isolate the customer ID number. """
    pattern = re.compile("Cust#[^0-9]+(\d+)")
    return pattern.findall(entry)[0]

# return a list of dicts,each element has full entry and customer id
parsed = [{"full_entry": sep + x,"cust_id": get_cust_number(x)} 
          for x in data.split(sep) if x]

# example parsed element
{'full_entry': "Serial#......... 12345678974566321\nCust#........... 123456\nCustomer Name... Humpfrey Bear\nBILL TO NO NAME. Bill To: 001166 - Some Company\nDATE...... 01/01/00\n\n'",'cust_id': '123456'}

现在使用set查找重复的Cust#并将重复的条目存储在dupes中：

seen = set()
dupes = list()

# iterate over each entry,store :cust_id: values in :seen: set.
# if :cust_id: is already in :seen:,it is a dupe.  store it in :dupes:.
for entry in parsed:
    if entry['cust_id'] in seen:
        dupes.append(entry['full_entry'])
    else:
        seen.add(entry['cust_id'])
        
dupes
["Serial#......... sgfdsfd546545645\nCust#........... 123456\nCustomer Name... Humpfrey Bear\nBILL TO NO NAME. Bill To: 0165487 - Some Other Company\nDATE...... 01/01/00\n\n'","Serial#......... JdsfrfdsgHG091797\nCust#........... 015648\nCustomer Name... Eric Cantona\nBILL TO NO NAME. Bill To: 9876524 - Big Big Company\nDATE...... 01/01/00\n\n'"]

我不明白为什么您的输出有第二个“汉普弗雷熊”条目，却有第一个“埃里克·坎通纳”条目。该答案将生成仅重复输出的列表（意味着第一个条目不存在）。