嘿，我该如何为使用tkinter在python中编写的剪刀，石头，剪刀写规则？

如何解决嘿，我该如何为使用tkinter在python中编写的剪刀，石头，剪刀写规则？

因此，我一直在尝试与tkinter一起编写岩石，纸张和剪刀游戏，以学习python。我制作了GUI，每次单击按钮后，该漫游器都会显示不同的动作。但是，更改按钮不会影响计分板。因为我是编码新手，所以我需要帮助编写规则。 请看一下代码。

# pictures on buttons
photo1 = PhotoImage(file=r"E:\ROCK.png")
photoimage = photo1.subsample(9,9)
photo2 = PhotoImage(file=r"E:\download.png")
photoimage1 = photo2.subsample(4,4)
photo3 = PhotoImage(file=r"E:\SCISSOR.png")
photoimage2 = photo3.subsample(4,4)

#bot's move

global list
global choice
list = [1,2,3,1,3]
choice = random.choice(list) 

global move
global imgbot
global bmove
bmove = int(choice)

#function of buttons

#function of Rock
def click():
    global move,imgbot,choice,i
    i = 1
    move = 1


    if choice == 1:
        imgbot = photoimage

    if choice == 2:
        imgbot = photoimage1

    if choice == 3:
        imgbot = photoimage2
    if move == 1 or move == 2 or move == 3:
        choice = random.choice(list)
        botmove.config(image=imgbot)


#function of paper
def click1():
    global move,i
    i = 2
    move = 2
    if choice == 1:
        imgbot = photoimage

    if choice == 2:
        imgbot = photoimage1

    if choice == 3:
        imgbot = photoimage2
    if move == 1 or move == 2 or move == 3:
        botmove.config(image=imgbot)
        choice = random.choice(list)

#function of scissor
def click2():
    global move,i
    i = 3
    move = 3
    if choice == 1:
        imgbot = photoimage

    if choice == 2:
        imgbot = photoimage1

    if choice == 3:
        imgbot = photoimage2
    if move == 1 or move == 2 or move == 3:
        botmove.config(image=imgbot)
        choice = random.choice(list)

 # components

#Score board
scorep = 0
scoreb = 0
Scoreboard = Label(window,text=str("BOT- ") + str(scoreb) + str(":") + str(scorep) + str(" -YOU "))

#other components
button2 = Button(window,text="Close Game",command=close,padx=20)
botmove = Button(window,padx=20,pady=20,image=photoimage3)
prock = Button(window,image=photoimage,command=click)
ppaper = Button(window,image=photoimage1,command=click1)
pscissor = Button(window,image=photoimage2,command=click2)

我希望能够在他们输赢时不断更新比分并显示“ WIN”，“ LOSE”或“ DRAW”，我可以自己进行定位。我将move定义为整数，这样我就可以写出“如果move-bmove =某物然后显示获胜，失败或平局”。存在全局变量“ i”，因为我正在尝试执行其他操作，但是它们失败了，因此您可以忽略“ i”。我没有包括整个代码，只有重要的部分和必要的上下文。

希望您能理解我的问题。感谢您的帮助。

解决方法

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import random

alternatives = ('rock','paper','scissors')

# we can emulate a 3x3 table with a nested dictionary
# the first layer is the player choice,the second is the result according to the bot choice
rules = {
    'rock': # if player chooses rock
        {'rock': 'draw','paper': 'loose','scissors': 'win'},# results according to bot choice
    'paper': {'rock': 'win','paper': 'draw','scissors': 'loose'},'scissors': {'rock': 'loose','paper': 'win','scissors': 'draw'}
}

# photos = { # whenever you have a collection objects of the same type (e.g. PhotoImage instances)
    # # it is a good idea to make a dictionary so you can dinamically access each item
    # key: PhotoImage(file=f'E:\\{key.upper()}.png') 
    # for key in alternatives
    # # this is called a 'dictionary comprehension' or 'dict-comprehension'
# }

# later you can get each photo with
# photos[player_move] # returns the PhotoImage object



score = [0,0] # player,bot

# then you can create a single function to update the score,regardless of the choice
# and call it when a player makes a move
def update_score(player_choice):
    ''' keep in mind
    score: list of [player,bot] integer scores
    player_choice: string with the player's choice,provided by the button click
    '''
    
    bot_choice = random.choice(alternatives)
    
    # `score` and `result` are mutable objects
    # therefore they are accessible in main and all its dependant namespaces
    # i.e. we can inspect `rules` and modify `score`
    # without calling `global` / `nonlocal` inside the function
    result = rules[player_choice][bot_choice]
    if result == 'win':
        score[0] += 1
        out = 'lucky dog!'
    elif result == 'loose':
        score[1] += 1
        out = 'what a looser...'
    else:
        out = 'we live to fight another day'
    
    # notice we already updated score,so we don't need a return line
    print(bot_choice,player_choice,'::',out)
    

使用

进行测试

for player_choice in random.choices(population=alternatives,weights=(1,1,1),k=20):
    update_score(player_choice)
    
# score_text = f'BOT {str(score[1])} : {str(score[0])} YOU'
score_text = (
    'BOT ' + 
    ' : '.join( # takes a sequence of strings and joins them into a single string
        list(map(str,score[::-1])) # iterates `score` backwards and applies string to each value
        ) +
    ' YOU'
)
print(score_text)