有人可以建议使用带有多个“ where”子句的DoctrineQueryBuilder进行此查询的方法吗？

如何解决有人可以建议使用带有多个“ where”子句的DoctrineQueryBuilder进行此查询的方法吗？

我是QueryBuilder的新手，我正在尝试执行POST请求（使用JSON）以检索数据库中的某些信息。

我正在使用数组，因为每个属性可以具有多个值。这是我当前正在发送的JSON：

{
    "name":["Martin"],"state":["Ohio","Texas"],"job":["Photographer","Reporter"]
}

这是我的数据库：

ID  |   NAME        |   FIRST_NAME  |   STATE       |   JOB             |   SPEAK_FRENCH
1   |   Martin      |   John        |   Ohio        |   Photographer    |   1
2   |   Martin      |   Max         |   Ohio        |   Reporter        |   1
3   |   Martin      |   Sophie      |   Texas       |   Model           |   1
4   |   Alexander   |   David       |   Kansas      |   Author          |   0
5   |   Archie      |   Kira        |   Maine       |   Photographer    |   1
6   |   Lushen      |   Albert      |   Nevada      |   Pilot,Model    |   1
7   |   Wilkins     |   Minnie      |   Utah        |   Tailor          |   0
8   |   Martin      |   Thomas      |   Texas       |   Reporter        |   1
9   |   Patino      |   Stephen     |   Virginia    |   Pilot,Reporter |   1
10  |   Ting        |   Maria       |   Nevada      |   Dentist         |   0
11  |   Brown       |   Barbara     |   Virginia    |   Reporter        |   1
12  |   Martin      |   William     |   Texas       |   Photographer    |   1
13  |   Zachary     |   Thomas      |   Virginia    |   Telephonist     |   1

我想要的请求：

SELECT * FROM 'application'
WHERE SPEAK_FRENCH = 1
AND NAME = "Martin"
AND STATE = "Ohio"
AND JOB LIKE "%Photographer%"
OR SPEAK_FRENCH = 1
AND NAME = "Martin"
AND STATE = "Ohio"
AND JOB LIKE "%Reporter%"
OR SPEAK_FRENCH = 1
AND NAME = "Martin"
AND STATE = "Texas"
AND JOB LIKE "%Photographer%"
OR SPEAK_FRENCH = 1
AND NAME = "Martin"
AND STATE = "Texas"
AND JOB LIKE "%Reporter%"

而我目前在Symfony中所做的工作却无法达到我想要的方式：

$repository = $this->getDoctrine()->getRepository(Application::class);
$query = $repository->createQueryBuilder('request');
$temp_name = 0;
$temp_state = 0;
$temp_job = 0;
foreach ($app->getName() as $name) {
    $temp_name = $temp_name + 1;

    $query = $query->orWhere('request.speakFrench = 1')
        ->andWhere('request.name LIKE :JSONname' . strval($temp_name))
        ->setParameter('JSONname' . strval($temp_name),$name);

    foreach ($app->getState() as $state) {
        $temp_state = $temp_state + 1;

        $query = $query->andWhere('request.state LIKE :JSONstate' . strval($temp_state))
            ->setParameter('JSONstate' . strval($temp_state),$state);

        foreach ($app->getJob() as $job) {
        $temp_job = $temp_job + 1;

        $query = $query->andWhere('request.job LIKE :JSONjob' . strval($temp_job))
            ->setParameter('JSONjob' . strval($temp_job),'%' . $job . '%');
        }
    }
}

我的目标是得到这个结果：

ID  |   NAME        |   FIRST_NAME  |   STATE       |   JOB             |   SPEAK_FRENCH
1   |   Martin      |   John        |   Ohio        |   Photographer    |   1
2   |   Martin      |   Max         |   Ohio        |   Reporter        |   1
8   |   Martin      |   Thomas      |   Texas       |   Reporter        |   1
12  |   Martin      |   William     |   Texas       |   Photographer    |   1

我的代码运行不正常，它没有发送任何错误，只返回了ID : 8。

我正在寻找一种只返回ID : 1,2,8 and 12的查询的方法。

非常感谢您将来的回答。

P.S：我正在运行Symfony 4.3.11。

解决方法

以下内容似乎是与您的要求相对应的有效查询：

SELECT * 
  FROM application
 WHERE SPEAK_FRENCH = 1
    AND NAME = "Martin"
    AND STATE = IN("Ohio","Texas")
    AND (JOB LIKE "%Photographer%" OR JOB LIKE "%Reporter%");

另外，请参见Is storing a delimited list in a database column really that bad?

,

借助“教义”，您可以为例：

    $queryBuilder = $this->createQueryBuilder('request');
    $queryBuilder
        ->andWhere($queryBuilder->expr()->andX(
            $queryBuilder->expr()->eq('user.speakFrench',':speakFrench'),$queryBuilder->expr()->like('request.name',':name'),$queryBuilder->expr()->in('request.state',':states'),$queryBuilder->expr()->in('request.job',':jobs'),))
        ->setParameter('speakFrench',true)
        ->setParameter('name','Martin')
        ->setParameter('states',['Ohio','Texas'])
        ->setParameter('jobs',['Photographer','Reporter'])
        ->getQuery()
        ->getResult();

那应该是一个好的开始。

要继续：

• 许多教义用法示例：Hot examples
• 检查Doctrine \ ORM \ Query \ Expr类，有很多有用的功能。 Doctrine Expr GitHub
• 查看提供许多示例的文档：Doctrine Query Builder