如何解决我的Spring-Boot自定义登录表单无法使用[更新]
我是Spring-Boot的新手,目前,我正在开发具有MySQL数据库连接的自定义登录表单。
所以我已经开发了注册功能,并且可以正常工作。
但是当我尝试登录一个帐户时,它总是显示“无效的用户名和密码”。
我正在使用Eclipse IDE。
下面是Controller类:WebMvcConfiguration.java
@ComponentScan("org.springframework.security.samples.mvc")
@Controller
@Configuration
public class WebMvcConfiguration implements WebMvcConfigurer {
@Override
public void addViewControllers(ViewControllerRegistry registry) {
registry.addViewController("/login").setViewName("login");
registry.setOrder(Ordered.HIGHEST_PRECEDENCE);
}
@GetMapping("/login")
public String login() {
return "login";
}
@PostMapping("/customerAccount")
public String authenticate() {
// authentication logic here
return "customerAccount";
}
@GetMapping("/adminDashboard")
public String adminDashboard() {
return "adminDashboard";
}
@GetMapping("/Category")
public String Category() {
return "Category";
}
@GetMapping("/Index")
public String Index() {
return "Index";
}
@PostMapping("/RatingAccount")
public String RatingAccount() {
return "RatingAccount";
}
public void addResourceHandlers(final ResourceHandlerRegistry registry) {
registry.addResourceHandler("/resources/static/**").addResourceLocations("/resources/static/");
}
}
下面是UserAccountController.java
@RestController
@Controller
public class UserAccountController {
@Autowired
private CustomerRepository userRepository;
@Autowired
private ConfirmationTokenRepository confirmationTokenRepository;
@Autowired
private EmailSenderService emailSenderService;
@RequestMapping(value="/register",method = RequestMethod.GET)
public ModelAndView displayRegistration(ModelAndView modelAndView,Customer user)
{
modelAndView.addObject("user",user);
modelAndView.setViewName("register");
return modelAndView;
}
@RequestMapping(value="/register",method = RequestMethod.POST)
public ModelAndView registerUser(ModelAndView modelAndView,Customer user)
{
Customer existingUser = userRepository.findByEmailIdIgnoreCase(user.getEmailId());
if(existingUser != null)
{
modelAndView.addObject("message","This email already exists!");
modelAndView.setViewName("error");
}
else
{
userRepository.save(user);
ConfirmationToken confirmationToken = new ConfirmationToken(user);
confirmationTokenRepository.save(confirmationToken);
SimpleMailMessage mailMessage = new SimpleMailMessage();
mailMessage.setTo(user.getEmailId());
mailMessage.setSubject("Complete Registration!");
mailMessage.setFrom("rukshan033@gmail.com");
mailMessage.setText("To confirm your account,please click here : "
+"http://localhost:8082/confirm-account?token="+confirmationToken.getConfirmationToken());
emailSenderService.sendEmail(mailMessage);
modelAndView.addObject("emailId",user.getEmailId());
modelAndView.setViewName("successfulRegisteration");
}
return modelAndView;
}
@RequestMapping(value="/confirm-account",method= {RequestMethod.GET,RequestMethod.POST})
public ModelAndView confirmUserAccount(ModelAndView modelAndView,@RequestParam("token")String confirmationToken)
{
ConfirmationToken token = confirmationTokenRepository.findByConfirmationToken(confirmationToken);
if(token != null)
{
Customer user = token.getCustomer();
//Customer user = userRepository.findByEmailIdIgnoreCase(token.getCustomer().getEmailId());
user.setEnabled(true);
userRepository.save(user);
modelAndView.setViewName("accountVerified");
}
else
{
modelAndView.addObject("message","The link is invalid or broken!");
modelAndView.setViewName("error");
}
return modelAndView;
}
@RequestMapping(value="/login",RequestMethod.POST})
// @ResponseBody
public ModelAndView login(ModelAndView modelAndView,@RequestParam("emailID")String email,@RequestParam("password")String password)
{
Customer user = userRepository.findByEmailIdIgnoreCase(email);
if(user == null) {
modelAndView.addObject("message1","Invalid E-mail. Please try again.");
modelAndView.setViewName("login");
}
else if (user != null && user.getPassword()!=password) {
modelAndView.addObject("message1","Incorrect password. Please try again.");
modelAndView.setViewName("login");
}
else if (user != null && user.getPassword()==password && user.isEnabled()==false) {
modelAndView.addObject("message1","E-mail is not verified. Check your inbox for the e=mail with a verification link.");
modelAndView.setViewName("login");
}
else if (user != null && user.getPassword()==password && user.isEnabled()==true) {
modelAndView.addObject("message1","Welcome! You are logged in.");
modelAndView.setViewName("customerAccount");
}
return modelAndView;
}
@RequestMapping(value="/customerDetails",method = RequestMethod.GET)
public ModelAndView displayCustomerList(ModelAndView modelAndView)
{
modelAndView.addObject("customerList",userRepository.findAll());
modelAndView.setViewName("customerDetails");
return modelAndView;
}
// getters and setters
public CustomerRepository getUserRepository() {
return userRepository;
}
public void setUserRepository(CustomerRepository userRepository) {
this.userRepository = userRepository;
}
public ConfirmationTokenRepository getConfirmationTokenRepository() {
return confirmationTokenRepository;
}
public void setConfirmationTokenRepository(ConfirmationTokenRepository confirmationTokenRepository) {
this.confirmationTokenRepository = confirmationTokenRepository;
}
public EmailSenderService getEmailSenderService() {
return emailSenderService;
}
public void setEmailSenderService(EmailSenderService emailSenderService) {
this.emailSenderService = emailSenderService;
}
}
下面是“安全配置”类:SecurityConfig.java
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter{
@Override
protected void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
.antMatchers(
"/Index/**","/Category/**","/register**","/css/**","/fonts/**","/icon-fonts/**","/images/**","/img/**","/js/**","/Source/**").permitAll()
.anyRequest().authenticated()
.and()
.formLogin()
.loginPage("/login")
.permitAll()
.and()
.logout()
.permitAll();
}
}
下面是Thymeleaf登录页面:login.html
<html xmlns:th="http://www.thymeleaf.org" xmlns:tiles="http://www.thymeleaf.org">
<head>
<title tiles:fragment="title">Login</title>
</head>
<body>
<div tiles:fragment="content">
<form name="f" th:action="@{/login}" method="post">
<fieldset>
<legend>Please Login</legend>
<div th:if="${param.error}" class="alert alert-error">
Invalid username and password.
</div>
<div th:if="${param.logout}" class="alert alert-success">
You have been logged out.
</div>
<label for="emailId">E-mail</label>
<input type="text" id="emailId" name="emailId"/>
<label for="password">Password</label>
<input type="password" id="password" name="password"/>
<div class="form-actions">
<button type="submit" class="btn">Log in</button>
</div>
</fieldset>
</form>
</div>
</body>
</html>
下面是我应重定向至的页面:customerAccount.html
<html lang="en" xmlns="http://www.w3.org/1999/xhtml"
xmlns:th="http://www.thymeleaf.org">
<head>
<title>Welcome</title>
</head>
<body>
<form th:action="@{/customerAccount}" method="post">
<center>
<h3 th:inline="text">Welcome [[${#httpServletRequest.remoteUser}]]</h3>
</center>
<form th:action="@{/logout}" method="post">
<input type="submit" value="Logout" />
</form>
</form>
</body>
</html>
编辑
新的UserDetailsService类:
public class CustomerDetailsService implements UserDetailsService{
@Autowired
private CustomerRepository customerRepository;
@Override
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
Customer customer = customerRepository.findByEmailIdIgnoreCase(username);
if (customer == null) {
throw new UsernameNotFoundException(username);
}
return new MyUserPrincipal(customer);
}
}
class MyUserPrincipal implements UserDetails {
private Customer customer;
public MyUserPrincipal(Customer customer) {
this.customer = customer;
}
@SuppressWarnings("unchecked")
@Override
public Collection<? extends GrantedAuthority> getAuthorities() {
// TODO Auto-generated method stub
Authentication auth = SecurityContextHolder.getContext().getAuthentication();
if (auth != null) {
return (Collection<GrantedAuthority>) auth.getAuthorities();
}
return null;
}
@Override
public String getPassword() {
return customer.getPassword();
}
@Override
public String getUsername() {
return customer.getEmailId();
}
@Override
public boolean isAccountNonExpired() {
return false;
}
@Override
public boolean isAccountNonLocked() {
return false;
}
@Override
public boolean isCredentialsNonExpired() {
return false;
}
@Override
public boolean isEnabled() {
return customer.isEnabled();
}
}
我添加了一些System.out.print()
,但发现我的UserAccountController
无法访问。 CustomerDetailsService
类也被访问,并且用户名正确传递。我该如何连接控制器?
解决方法
我建议使用Spring Security。看到这是您每次创建新应用程序时都会复制的代码,最好对其进行清理并让其框架正常工作。 ;)
首先,您对WebSecurityConfigurerAdapter
的实现
@Configuration
public class SpringSecurityConfig extends WebSecurityConfigurerAdapter {
private static final String USER_BY_USERNAME_QUERY = "select Email,Wachtwoord,Activatie from users where Email = ?" ;
private static final String AUTHORITIES_BY_USERNAME_QUERY = "select Email,Toegang from users where Email = ?" ;
@Autowired
private AccessDeniedHandler accessDeniedHandler;
@Autowired
private PasswordEncoder encoder;
@Autowired
private DataSource dataSource;
@Override
protected void configure(HttpSecurity http) throws Exception {
http.csrf().disable()
.authorizeRequests()
.antMatchers("/","/public/**","/css/**","/js/**","/font/**","/img/**","/scss/**","/error/**").permitAll()
.antMatchers("/mymt/**").hasAnyRole("MEMBER","ADMIN","GUEST","BOARD")
.antMatchers("/admin/**").hasAnyRole("ADMIN","BOARD")
.antMatchers("/support/**").hasAnyRole("ADMIN","BOARD")
.anyRequest().authenticated()
.and()
.formLogin()
.loginPage("/login")
.permitAll()
.and()
.logout()
.permitAll()
.and()
.exceptionHandling().accessDeniedHandler(accessDeniedHandler)
;
}
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.jdbcAuthentication()
.passwordEncoder(encoder)
.dataSource(dataSource)
.usersByUsernameQuery(USER_BY_USERNAME_QUERY)
.authoritiesByUsernameQuery(AUTHORITIES_BY_USERNAME_QUERY)
;
}
}
首先,我加载在主应用程序中定义为PasswordEncoder
方法的@Bean
。我使用BCryptPasswordEncoder
进行密码哈希处理。
我从Spring Boot Starter的内存中加载了DataSource
。为我用作默认数据库(我的默认持久性单元,因为我使用Spring Data jpa)配置了这个数据库
对于授权的配置,我首先禁用跨站点引用作为一种安全措施。然后,我配置所有路径,并告诉Spring谁可以访问Web应用程序的哪一部分。在我的数据库中,这些角色被记为ROLE_MEMBER
,ROLE_BOARD
,... ... Spring Security本身会丢弃ROLE_
,但需要它存在。
此后,我添加formLogin并将其指向/login
的URL,并允许所有角色访问登录页面。
我还添加了一些注销功能和异常处理。您可以根据需要将其忽略。
然后我配置身份验证。
在这里,我使用jdbcAuthentication
通过数据库登录。
我给编码器提供密码,数据源,然后使用我预编译的两个查询,分别提供用户信息和用户角色。
就是这样。
我的控制器非常简单
@Controller
@RequestMapping("/login")
public class BasicLoginController {
private static final String LOGON = "authentication/login";
@GetMapping
public String showLogin() {
return LOGON;
}
}
我的主菜单如下:
@SpringBootApplication
@EnableGlobalMethodSecurity(securedEnabled = true)
public class MyMT extends SpringBootServletInitializer {
public static void main(String[] args) {
ConfigurableApplicationContext ctx = SpringApplication.run(MyMT.class,args);
}
@Bean
public BCryptPasswordEncoder encoder() {
return new BCryptPasswordEncoder();
}
@Bean
public Logger logger() {
return Logger.getLogger("main");
}
}
我的HTML页面如下:
<!DOCTYPE html>
<html lang="en" xmlns:th="http://www.thymeleaf.org">
<head>
<meta charset="UTF-8">
<title>MyMT Login</title>
<div th:insert="fragments/header :: header-css" />
</head>
<body>
<div class="bgMask">
<div th:insert="fragments/header :: nav-header (active='Home')" />
<main>
<div class="container">
<h1>Login</h1>
<!-- Form -->
<form class="text-center" style="color: #757575;" method="post">
<p>Om toegang te krijgen tot het besloten gedeelte moet je een geldige login voorzien.</p>
<div class="row" th:if="${param.error}">
<div class="col-md-3"></div>
<div class=" col-md-6 alert alert-danger custom-alert">
Invalid username and/or password.
</div>
<div class="col-md-3"></div>
</div>
<div class="row" th:if="${param.logout}">
<div class="col-md-3"></div>
<div class="col-md-6 alert alert-info custom-alert">
You have been logged out.
</div>
<div class="col-md-3"></div>
</div>
<!-- Name -->
<div class="md-form mt-3 row">
<div class="col-md-3"></div>
<div class="col-md-6">
<input type="text" id="username" class="form-control" name="username" required>
<label for="username">Email</label>
</div>
<div class="col-md-3"></div>
</div>
<!-- E-mai -->
<div class="md-form row">
<div class="col-md-3"></div>
<div class="col-md-6">
<input type="password" id="password" class="form-control" name="password" required>
<label for="password">Password</label>
</div>
<div class="col-md-3"></div>
</div>
<!-- Sign in button -->
<input type="submit" value="Login" name="login" class="btn btn-outline-info btn-rounded btn-block z-depth-0 my-4 waves-effect" />
</form>
<!-- Form -->
</div>
</main>
<div th:insert="fragments/footer :: footer-scripts" />
<div th:insert="fragments/footer :: footer-impl" />
</div>
</body>
</html>
在这里您可以看到两个输入字段,分别是用户名和密码名。
多数民众赞成在登录配置。现在,您可以使用所有控制器,而不必为其添加安全性。
用干净的代码术语。到处都增加安全性是一个横切关注点。 Spring安全通过使用面向方面的编程技巧来解决此问题。换一种说法。它拦截HttpRequest并首先检查用户。安全性会自动启动一个包含用户信息的会话,并对此会话进行检查。
我希望简短的说明有助于您进行登录。 :)
,.loginPage("/login")
您已经在Spring Security中声明了login
路径,因此Spring security将拦截您对该路径的调用,并且永远不会进入您的控制器。
所以您的控制器,都不是
public ModelAndView login(ModelAndView modelAndView,@RequestParam("emailID")String email,@RequestParam("password")String password)
或
@GetMapping("/login")
public String login() {
return "login";
}
将起作用。
您需要提供自己的身份验证提供程序,例如this。或者,您可以使用默认提供程序并提供UserDetailsService
实现,例如this。
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。