从抓取的数据创建嵌套字典Scrapy Python 使用scrapy从this website刮下一个货币值表并创建此列表：到目前为止，我的代码：我想要的输出将是这样的：

如何解决从抓取的数据创建嵌套字典Scrapy Python 使用scrapy从this website刮下一个货币值表并创建此列表：到目前为止，我的代码：我想要的输出将是这样的：

我不确定我是否需要使用从网站抓取的数据直接生成字典，还是最好先创建一个列表，但这是我所做的（如果可能，我不想使用熊猫）：

使用scrapy从this website刮下一个货币值表并创建此列表：

# the value order is "Currency_name",BRL,USD,EUR,GBP,JPY,CHF,CAD,AUD
[" BRL","1","0,1800",1517",1361","19,0340",1633",2372",2501"," USD","5,5571",8428",7564","105,78",9075","1,3181",3897"," EUR","6,5938",1866",8977","125,49",0769",5640",6488"," GBP","7,3460",3219",1140","139,82",1997",7424",8370"," JPY",05254",0095",0080",00715",0086",01246",01314"," CHF",1236",1019",9286",8335","116,53",4525",5312"," CAD","4,2160",7587",6394",5739","80,25",6886",0543"," AUD","3,9989",7196",6065",5444","76,12",6532",9485","1"]

到目前为止，我的代码：

import scrapy

# inside scrapy.Spider class
def parse(self,response):
    currency_table = response.css("#exchange_rates_1 > tbody > tr > td::text").extract()
    item_list = []
    for data in currency_table:
        items = data.strip("\t").strip("\n").strip("\t") # removing nonsense
        if items.startswith("\xa0"): # country flag code
            item_list.append(items.strip("\xa0"))
        elif items != "":
            item_list.append(items)

我想要的输出将是这样的：

currency_dict = {
            "BRL": {
                "Real": 1,"Dollar": value,"Euro": value,"Pound": value,"Yen": value,"Swiss Frank": value,"Canadian Dollar": value,"Australian Dollar": value,},"USD": {
                "Real": value,"Dollar": 1,...
            },# continues for all currencies
        }

解决方法

类似的事情应该起作用：

import pprint

# from https://stackoverflow.com/a/312464/
def chunks(lst,n):
    """Yield successive n-sized chunks from lst."""
    for i in range(0,len(lst),n):
        yield lst[i:i + n]

cur_lst = ["Real","Dollar","Euro","Pound","Yen","Swiss Frank","Canadian Dollar","Australian Dollar"]

data = [" BRL","1","0,1800",1517",1361","19,0340",1633",2372",2501"," USD","5,5571",8428",7564","105,78",9075","1,3181",3897"," EUR","6,5938",1866",8977","125,49",0769",5640",6488"," GBP","7,3460",3219",1140","139,82",1997",7424",8370"," JPY",05254",0095",0080",00715",0086",01246",01314"," CHF",1236",1019",9286",8335","116,53",4525",5312"," CAD","4,2160",7587",6394",5739","80,25",6886",0543"," AUD","3,9989",7196",6065",5444","76,12",6532",9485","1"]

currency_dict = {}
for cur_name,*cur_data in chunks(data,9):
    data_obj = {}
    for name,value in zip(cur_lst,cur_data):
        # Python doesn't like a comma used as a decimal point
        data_obj[name] = float(value.replace(",","."))

    currency_dict[cur_name.strip()] = data_obj
    
pprint.pprint(currency_dict)

输出：

{'AUD': {'Australian Dollar': 1.0,'Canadian Dollar': 0.9485,'Dollar': 0.7196,'Euro': 0.6065,'Pound': 0.5444,'Real': 3.9989,'Swiss Frank': 0.6532,'Yen': 76.12},'BRL': {'Australian Dollar': 0.2501,'Canadian Dollar': 0.2372,'Dollar': 0.18,'Euro': 0.1517,'Pound': 0.1361,'Real': 1.0,'Swiss Frank': 0.1633,'Yen': 19.034},'CAD': {'Australian Dollar': 1.0543,'Canadian Dollar': 1.0,'Dollar': 0.7587,'Euro': 0.6394,'Pound': 0.5739,'Real': 4.216,'Swiss Frank': 0.6886,'Yen': 80.25},'CHF': {'Australian Dollar': 1.5312,'Canadian Dollar': 1.4525,'Dollar': 1.1019,'Euro': 0.9286,'Pound': 0.8335,'Real': 6.1236,'Swiss Frank': 1.0,'Yen': 116.53},'EUR': {'Australian Dollar': 1.6488,'Canadian Dollar': 1.564,'Dollar': 1.1866,'Euro': 1.0,'Pound': 0.8977,'Real': 6.5938,'Swiss Frank': 1.0769,'Yen': 125.49},'GBP': {'Australian Dollar': 1.837,'Canadian Dollar': 1.7424,'Dollar': 1.3219,'Euro': 1.114,'Pound': 1.0,'Real': 7.346,'Swiss Frank': 1.1997,'Yen': 139.82},'JPY': {'Australian Dollar': 0.01314,'Canadian Dollar': 0.01246,'Dollar': 0.0095,'Euro': 0.008,'Pound': 0.00715,'Real': 0.05254,'Swiss Frank': 0.0086,'Yen': 1.0},'USD': {'Australian Dollar': 1.3897,'Canadian Dollar': 1.3181,'Dollar': 1.0,'Euro': 0.8428,'Pound': 0.7564,'Real': 5.5571,'Swiss Frank': 0.9075,'Yen': 105.78}}