颜色链问题和非重复性

如何解决颜色链问题和非重复性

python非常新,并试图重新创建我在学校玩过的游戏。对于此游戏,我需要随机生成这些炸弹,如果它们被击中,则会将您的银行帐户减少为零,并将正方形的炸弹正方形的颜色更改为红色(安全的则变为绿色)。 我遇到的问题是:

  • 我想将炸弹的颜色更改为红色,尽管他们不这样做,只是保持白色,但是安全的颜色变为绿色
  • 对于炸弹的坐标,我想确保所有炸弹的坐标都不相等,我想使其炸弹重新滚动重复的炸弹

对其中任何一项的任何帮助将不胜感激

#--------------------------------Pirate Game-----------------------------------------------------------------------------------------------------

#initilising
import pygame
import random
black = (0,0)
white = (255,255,255)
green = (0,0)
red = (255,0)
 

width = 20
height = 20
margin = 5#gap between 

current = 0
bank = 0
turnnumber = 0

grid = []
for row in range(10):
    # Add an empty array that will hold each cell
    # in this row
    grid.append([])
    for column in range(10):
        grid[row].append(0) 
 

pygame.init()
GameR = [600,600]
gameD = pygame.display.set_mode(GameR)
pygame.display.set_caption("Pirate Game")
 
done = False

clock = pygame.time.Clock()
#-------------------------------------------------------------------------------------------------------
#FUNCTIONS
def bombs():
    for i in range(5):
        row = random.randrange(10)
        column = random.randrange(10)
        grid[row][column] = 2
        print(row,column)



#---------------------------------------------------------------------------
#MAIN LOOP:

done = False

clock = pygame.time.Clock()
while not done:
    for event in pygame.event.get():  
        if event.type == pygame.QUIT:  
            done = True
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_SPACE:
                bombs()
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_SPACE:
                print("Dont Press that")
        elif event.type == pygame.MOUSEBUTTONDOWN:
            pos = pygame.mouse.get_pos()
            # Change the x/y screen coordinates to grid coordinates
            column = pos[0] // (width + margin)
            row = pos[1] // (height + margin)
            if grid[row][column] == 2:
                print('Boom')
            if grid[row][column] != 2:
                grid[row][column] = 1
                print("Click ",pos,"Grid coordinates: ",row,column)

                
    gameD.fill(black)
 
    #Draw the grid
    for row in range(10):
        for column in range(10):
            color = white
            if grid[row][column] == 1:
                color = green
            elif grid[row][column] == 2:
                colour = red
            pygame.draw.rect(gameD,color,[(margin +
                               width) * column + margin,(margin + height) * row + margin,width,height])
 
    
    clock.tick(60)
    pygame.display.flip()
 
pygame.quit()

解决方法

首先有一个错字:color = red,而不是colour = red

无论如何,您都必须更改游戏逻辑。对于未单击的单元格,请使用值0和2;对于已单击的单元格,请使用值1和3。通过0初始化网格的所有字段。通过将2分配给随机单元,将随机炸弹放在网格上。
单击值为0的单元格时,将其值更改为1。单击带有炸弹(值2)的单元格,然后将其更改为3:

while not done:
    # [...]

    for event in pygame.event.get():  
        # [...]

        elif event.type == pygame.MOUSEBUTTONDOWN:
            # Change the x/y screen coordinates to grid coordinates
            column = event.pos[0] // (width + margin)
            row = event.pos[1] // (height + margin)
            if grid[row][column] == 2:
                print('Boom')
                grid[row][column] = 3
            if grid[row][column] == 0:
                grid[row][column] = 1
                print("Click ",event.pos,"Grid coordinates: ",row,column)

绘制网格时,所有单元格都必须绘制为白色。除了单元格的值为1。在这种情况下,其颜色为绿色。如果单元格的值为3,则其颜色为红色:

while not done:
    # [...]

    #Draw the grid
    for row in range(10):
        for column in range(10):
            color = white
            if grid[row][column] == 1:
                color = green
            elif grid[row][column] == 3:
                color = red
            cell_rect = ((margin + width) * column + margin,(margin + height) * row + margin,width,height)
            pygame.draw.rect(gameD,color,cell_rect)

完整示例:

#initilising
import pygame
import random
black = (0,0)
white = (255,255,255)
green = (0,0)
red = (255,0)
 
width = 20
height = 20
margin = 5#gap between 

current = 0
bank = 0
turnnumber = 0

grid = []
for row in range(10):
    # Add an empty array that will hold each cell
    # in this row
    grid.append([])
    for column in range(10):
        grid[row].append(0) 
 
pygame.init()
GameR = [600,600]
gameD = pygame.display.set_mode(GameR)
pygame.display.set_caption("Pirate Game")
 
done = False
clock = pygame.time.Clock()
#-------------------------------------------------------------------------------------------------------
#FUNCTIONS
def bombs():
    for i in range(5):
        row = random.randrange(10)
        column = random.randrange(10)
        grid[row][column] = 2
        print(row,column)

bombs()

#---------------------------------------------------------------------------
#MAIN LOOP:

done = False

clock = pygame.time.Clock()
while not done:
    for event in pygame.event.get():  
        if event.type == pygame.QUIT:  
            done = True
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_SPACE:
                bombs()
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_SPACE:
                print("Dont Press that")
        elif event.type == pygame.MOUSEBUTTONDOWN:
            # Change the x/y screen coordinates to grid coordinates
            column = event.pos[0] // (width + margin)
            row = event.pos[1] // (height + margin)
            if grid[row][column] == 2:
                print('Boom')
                grid[row][column] = 3
            if grid[row][column] == 0:
                grid[row][column] = 1
                print("Click ",column)
           
    gameD.fill(black)
 
    #Draw the grid
    for row in range(10):
        for column in range(10):
            color = white
            if grid[row][column] == 1:
                color = green
            elif grid[row][column] == 3:
                color = red
            cell_rect = ((margin + width) * column + margin,cell_rect)
 
    clock.tick(60)
    pygame.display.flip()
 
pygame.quit()

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