如何在python中的字典中搜索多个值？

如何解决如何在python中的字典中搜索多个值？

我是编码的新手...我必须从数据库创建字典（我相信我能够做到），但是我还没有找到任何有关如何搜索多个值的示例。在这种情况下，我希望代码带给我所有数字都匹配的人的名字（AGATC，AATG和TATC），而不仅仅是一个。 因此，例如，如果输入为2 8 3（我的变量count1 count2 count3），则结果应为Alice。

任何帮助/指导将不胜感激。

这是我的字典的样子：

{'Alice': OrderedDict([('AGATC','2'),('AATG','8'),('TATC','3')]),'Bob': OrderedDict([('AGATC','4'),'1'),'5')])
 ... 

这是我到目前为止的代码：

from sys import argv
import csv
import re

#Opens the database and the sequence specified in the command-line argument
if len(argv) == 3:
    database = csv.DictReader(open(argv[1],'r')) #opens the file in dictionary format
    s = open(argv[2])
    sequence = s.read()
else:
    print("Missing command-line argument")

#Counts how many times STR repeats in the sequence by changing the STR definition to the maximum it found

str1 = "AGATC"
count1 = 0
while str1 in sequence:
    count1 += 1
    str1 += "AGATC"
print(count1)

str2 = "AATG"
count2 = 0
while str2 in sequence:
    count2 += 1
    str2 += "AATG"
print(count2)

str3 = "TATC"
count3 = 0
while str3 in sequence:
    count3 += 1
    str3 += "TATC"
print(count3)

#creates an empty dictionary
data_list = {}

#fill the dictionary
for row in database:
    key = row.pop('name')
    data_list[key] = row
print(data_list)

解决方法

我绝对同意先前关于使用更好的数据结构的评论，我相信以下内容可能对您现在有帮助：

from collections import OrderedDict 

x = {'Alice': OrderedDict([('AGATC','2'),('AATG','8'),('TATC','3')]),'Bob': OrderedDict([('AGATC','4'),'1'),'5')])}

lst = [2,8,3]

for k in x.keys():
    if lst == [int(y) for y in x[k].values()]:
        print(k)

,

这就是我的解决方案：

from sys import argv
import csv
import re

if len(argv) == 3:
    database = csv.DictReader(open(argv[1],'r')) 
    s = open(argv[2])
    sequence = s.read()
else:
    print("Missing command-line argument")

str1 = "AGATC"
count1 = 0
while str1 in sequence:
    count1 += 1
    str1 += "AGATC"

str2 = "AATG"
count2 = 0
while str2 in sequence:
    count2 += 1
    str2 += "AATG"

str3 = "TATC"
count3 = 0
while str3 in sequence:
    count3 += 1
    str3 += "TATC"

lst = [count1,count2,count3]

data_list = {}

for row in database:
    key = row.pop('name')
    data_list[key] = row
# print(data_list)

indicator = 0
for i in data_list.keys(): 
    if lst == [int(y) for y in data_list[i].values()]: 
        print(i)
        indicator += 1

if indicator == 0:
    print("No match")