如何解决从.txt文件中读取时间,然后倒计时到该时间
我有一个名为sorted_passes.txt的文本文件,其内容如下:
- NOAA18 23/08/2020 10:56:46最大海拔:67
- NOAA19 23/08/2020 19:08:02最大海拔:74
- NOAA15 23/08/2020 20:12:44最大海拔:87
- NOAA18 23/08/2020 22:19:47最大海拔:90
我想让一个计时器执行以下任一操作:
- 在.txt文件中向下计数到下一次,然后在该时间之后,再次向下计数到下一次。
- 在.txt文件中倒数一次
我的计划是最终通过连接到树莓派的MAX7219 LED板显示倒数计时器。
到目前为止,我有以下python代码:
# calculate time until next pass
from datetime import datetime
futuredate = datetime.strptime('10:56:46','%H:%M:%S')
nowdate = datetime.now()
count = int((futuredate-nowdate).total_seconds())
days = count//86400
hours = (count-days*86400)//3600
minutes = (count-days*86400-hours*3600)//60
seconds = count-days*86400-hours*3600-minutes*60
print("Next Pass: {}h:{}m:{}s".format(hours,minutes,seconds))
解决方法
这应该使您入门:
from datetime import datetime
from time import sleep
def compare(event):
"""Return True if it's counting down,false if the time already passed"""
now = datetime.now()
if now <= event:
diff = event - now
print("Countdown: {}".format(diff))
return True
else:
return False
def extract_timestamp(line):
"""Extract datetime from string:
NOAA18 23/08/2020 10:56:46 Max Elev: 67
"""
time_stamp = line[7:][:-14]
time_event = datetime.strptime(time_stamp,'%d/%m/%Y %H:%M:%S')
return time_event
def open_file():
with open('sorted_passes.txt','r') as f:
return f.readlines()
data = open_file()
# iterate through the lines of the file
for line in data:
ts = extract_timestamp(line)
while compare(ts):
sleep(1)
else:
print("Next event")
continue
print("Finished")
这将打印一个倒计时语句,其中包含需要花费多长时间,一秒钟的睡眠时间。否则它将转到下一个事件,直到选中所有行。
您需要确保文件日期是递增的(例如,新行总是比之前的行晚)。
示例输出(我在最后一行中手动更改了日期):
Next event
Next event
Next event
Countdown: 0:00:03.531014
Countdown: 0:00:02.526724
Countdown: 0:00:01.524277
Countdown: 0:00:00.518995
Finished
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