如何解决从下拉菜单Angular中删除选定的值
有4个相互关联的选择选项,因此当我从第一个选择一个选项时,应该从其他三个选择选项中删除该值
// LIST TARGET SLAB
getTargetSlab() {
this.riderservice.getTargetSlab().subscribe(res => {
this.target_slab = res['success'].data;
this.target_slab1 = res["success"].data;
this.target_slab2 = res["success"].data;
this.target_slab3 = res["success"].data;
this.target_slab4 = res["success"].data;
});
}
// FUNCTION TO REMOVE SELECTED TARGET PLAN
removeSelectedTargetSlab(index,slab) {
switch (index) {
case 1: {
this.target_slab2 = this.target_slab.filter(element => element != slab);
this.target_slab3 = this.target_slab.filter(element => element != slab);
this.target_slab4 = this.target_slab.filter(element => element != slab);
break;
}
case 2: {
this.target_slab1 = this.target_slab1.filter(element => element != slab);
this.target_slab3 = this.target_slab3.filter(element => element != slab);
this.target_slab4 = this.target_slab4.filter(element => element != slab);
break;
}
case 3: {
this.target_slab1 = this.target_slab1.filter(element => element != slab);
this.target_slab2 = this.target_slab2.filter(element => element != slab);
this.target_slab4 = this.target_slab4.filter(element => element != slab);
break;
}
case 4: {
this.target_slab1 = this.target_slab1.filter(element => element != slab);
this.target_slab2 = this.target_slab2.filter(element => element != slab);
this.target_slab3 = this.target_slab3.filter(element => element != slab);
break;
}
}
}
上面的代码是我尝试过的component.ts文件。
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