JavaScript：对象的Make和Filter / Create Date明智数组即Skype聊天记录视图

如何解决JavaScript：对象的Make和Filter / Create Date明智数组即Skype聊天记录视图

最近两个小时我一直在尝试这种方法，虽然搜索了很多，但是找不到任何解决方案，我正在从数据库中获取数据，并且有时间戳。

我想按日期过滤记录，即，如果有2020-08-20日期的数据，则创建一个对象，然后将一个日期中的所有天数设置为一个对象。

我要提取的对象：

[
    {
        "id": 16,"activity": "Amazon 16","type": "delivery_arrival","url": "www.google.com","created_at": "2020-08-25T12:14:13.000Z","updated_at": "2020-08-25T12:14:13.000Z"
    },{
        "id": 15,"activity": "Amazon 15","created_at": "2020-08-25T12:14:10.000Z","updated_at": "2020-08-25T12:14:10.000Z"
    },{
        "id": 14,"activity": "Amazon 14","created_at": "2020-08-25T12:14:07.000Z","updated_at": "2020-08-25T12:14:07.000Z"
    },{
        "id": 13,"activity": "Amazon 13","created_at": "2020-08-25T12:14:03.000Z","updated_at": "2020-08-25T12:14:03.000Z"
    },{
        "id": 12,"activity": "Amazon 12","created_at": "2020-08-25T12:13:59.000Z","updated_at": "2020-08-25T12:13:59.000Z"
    },{
        "id": 11,"activity": "Amazon 11","created_at": "2020-08-25T12:13:51.000Z","updated_at": "2020-08-25T12:13:51.000Z"
    },{
        "id": 10,"activity": "Amazon 10","created_at": "2020-08-25T12:13:46.000Z","updated_at": "2020-08-25T12:13:46.000Z"
    },{
        "id": 9,"activity": "Amazon 9","created_at": "2020-08-25T12:13:40.000Z","updated_at": "2020-08-25T12:13:40.000Z"
    },{
        "id": 8,"activity": "Amazon 8","created_at": "2020-08-25T12:13:33.000Z","updated_at": "2020-08-25T12:13:33.000Z"
    },{
        "id": 7,"activity": "Amazon 7","created_at": "2020-08-25T12:13:30.000Z","updated_at": "2020-08-25T12:13:30.000Z"
    }
]

我想要的是：

[
    {
        "date": "2020-08-20","activities": [
            {
                "activity": "name1"
            },{
                "activity": "name2"
            }
        ]
    },{
        "date": "2020-08-19",{
                "activity": "name2"
            }
        ]
    }
]

此外，还有分页，并且数据必须降序。

解决方法

您可以将https://momentjs.com/和filter与is between一起使用 然后是sort和is after；我还将建议Ramda's Group By（如果您已经在那儿，则Ramda的过滤器和排序是不可变的，则Array.prototype.sort的排序不是）