如何解决SQL中的Cte中的Cte
我遇到了一种情况,我需要根据CTE中CTE的结果按条件逐个应用。
表1如下
+---+---+---+---+
| x | y | z | w |
+---+---+---+---+
| 1 | 2 | 3 | 1 |
| 2 | 3 | 4 | 2 |
| 3 | 2 | 5 | 3 |
| 1 | 2 | 6 | 2 |
+---+---+---+---+
表2如下
+---+---+-----+---+
| a | b | c | d |
+---+---+-----+---+
| 1 | m | 100 | 1 |
| 2 | n | 23 | 2 |
| 4 | o | 34 | 4 |
| 1 | m | 23 | 2 |
+---+---+-----+---+
假设我在名为TAB的表中具有以下sql查询的数据
with cte as (
select x,y,z from table1),cte1 as (select a,b,c from table2)
select cte.x,cte1.y,cte1.z,cte2.b,cte2.c from cte left join cte1 on cte.x=cte.a and cte1.w=cte2.d
上述CTE的结果如下
+---+---+---+---+---+-----+
| x | y | z | w | b | c |
+---+---+---+---+---+-----+
| 1 | 2 | 3 | 1 | m | 100 |
| 2 | 3 | 4 | 2 | n | 23 |
| 1 | 2 | 6 | 2 | m | 23 |
+---+---+---+---+---+-----+
我想从表TAB中查询以下内容
select * from TAB where (X||b) in (select (X||b) from TAB group by (X||Y) having sum(c)=123)
我正在尝试制定如下的SQL查询,但它并非我所期望的:
select * from (
with cte as (
select x,cte2.c from cte left join cte1 on cte.x=cte.a) as TAB
where ((X||b) in (select (X||b) from TAB group by (X||Y) having sum(c)=123))
最终结果必须如下
+---+---+---+---+---+-----+
| x | y | z | w | b | c |
+---+---+---+---+---+-----+
| 1 | 2 | 3 | 1 | m | 100 |
| 1 | 2 | 6 | 2 | m | 23 |
+---+---+---+---+---+-----+
解决方法
我不认为DB2允许在子查询中或嵌套CTE。为什么不只使用另一个CTE来编写此代码?
with cte as (
select x,y,z from
table1
),cte1 as (
select a,b,c
from table2
),tab as (
select cte.x,cte1.y,cte1.z,cte1.w,cte2.b,cte2.c
from cte left join
cte1
on cte.x=cte.a and cte1.w=cte2.d
)
select *
from TAB
where (X||b) in (select (X||b) from TAB group by (X||Y) having sum(c)=123);
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