使用rank时无法将窗口调用分解为组

如何解决使用rank时无法将窗口调用分解为组

我有一个属性数据集，我正在尝试按属性计数对每个细分进行排名。然后，我想将具有大多数属性的段分配为管理这些属性的xml_id的段。我已经尝试过了：

select
    yyyy_mm_dd,xml_id,ps_segment
from(
    select
        pspd.yyyy_mm_dd,xppd.xml_id,ps.ps_segment,count(pspd.property_id) as property_count.
        rank() over (partition by pspd.yyyy_mm_dd order by count(pspd.property_id) desc) rn 
    from(
        select
            yyyy_mm_dd,property_id
        from
            t1
    ) pspd
    left join(
        select
            yyyy_mm_dd,property_id,xml_id
        from
            t2
    ) xppd on xppd.property_id = pspd.property_id and xppd.yyyy_mm_dd = pspd.yyyy_mm_dd
    inner join
        t3 ps on ps.property_id = property_id
    group by
        1,2,3
) x
where
    rn = 1

以上内容引发以下错误：

编译语句时出错：失败：SemanticException无法将窗口调用分解为组。至少1组必须仅取决于输入列。还要检查循环依赖性。基本错误：org.apache.hadoop.hive.ql.parse.SemanticException：第5:50行表达式不在GROUP BY键'property_count'

中

因此，xml_id本质上以ps_segment结尾，而{{1}}具有最高的属性计数。我在查询中做错了什么？

解决方法

我自己解决了此问题，以下查询有效。看来我应该一直使用ROW_NUMBER()而不是RANK()：

select
    yyyy_mm_dd,xml_id,ps_segment
from(
    select
        pspd.yyyy_mm_dd,xppd.xml_id,ps.ps_segment,count(pspd.property_id) as property_count,ROW_NUMBER() over (partition by pspd.yyyy_mm_dd,xml_id order by count(pspd.property_id) desc) rn
    from(
        select
            yyyy_mm_dd,property_id
        from
            t1
        where
            and yyyy_mm_dd = '2019-10-10'
    ) pspd
    left join(
        select
            yyyy_mm_dd,property_id,xml_id
        from
            t2
        where
            yyyy_mm_dd = '2019-10-10'
    ) xppd on xppd.property_id = pspd.property_id and xppd.yyyy_mm_dd = pspd.yyyy_mm_dd
    inner join
        t3 ps on ps.hotel_id = pspd.hotel_id
    group by
        1,2,3
) x
where
    rn = 1