从SQLite获取当前周数据和当年数据的总和

如何解决从SQLite获取当前周数据和当年数据的总和

我有一个SQLite数据库，sales表如下所示，

| Id | quantity |     dateTime     |
------------------------------------
| 1  | 10       | 2019-12-25 12:55 |
| 2  | 05       | 2019-12-30 12:55 |
| 3  | 25       | 2020-08-23 12:55 |
| 4  | 25       | 2020-08-24 12:55 |
| 5  | 56       | 2020-08-25 12:55 |
| 6  | 25       | 2020-08-26 12:55 |
| 7  | 12       | 2020-08-27 12:55 |
| 8  | 30       | 2020-08-28 12:55 |
| 9  | 40       | 2020-08-29 12:55 |

我需要获取（从一月到十二月）的当前周数据（从星期一到星期日）和当前年的数据。因此，如果我今天通过日期，则只需要按如下所示的天数获取“当前周”销售数据组，

如果我通过今天的日期和时间（2020-08-28 13:55），查询应该给我这样的本周数据，

Day        Sold Items (SUM(quantity))
Monday     20
Tuesday    25
Wednesday  10
Thursday   50
Friday     60
Saturday   0 (If the date hasn't come yet I need to get 0)
Sunday     0

与当我传递“当前日期”时的“当前年份”数据相同，

Month      Sold Items (SUM(quantity))
JAN        20
FEB        25
MAR        10
APR        50
MAY        60
JUN        0 (If the month hasn't come yet I need to get 0)
JUL        0
...        ...

我在SQLite中尝试了多个查询，但无法获得所需的信息。这是我尝试过的查询，

Weekly Data (This one gave me past week data also)
SELECT SUM(quantity) as  quantity,strftime('%w',dateTime) as Day
From sales
Group by strftime('%w',dateTime)

Monthly Data
SELECT SUM(quantity) as  quantity,strftime('%m',dateTime) as Month
From sales
Group by strftime('%m',dateTime)

那么有人可以帮助我实现这一目标吗？预先感谢。

解决方法

对于当前周的总数，您需要一个CTE来返回日期名称，而另一个CTE则返回当前星期的星期一。
您必须交叉连接这些CTE，并保持表的聚集状态：

with 
  days as (
    select 1 nr,'Monday' day union all
    select 2,'Tuesday' union all
    select 3,'Wednesday' union all
    select 4,'Thursday' union all
    select 5,'Friday' union all
    select 6,'Saturday' union all
    select 7,'Sunday'
  ),weekMonday as (
    select date(
        'now',case when strftime('%w','now') <> '1' then '-7 day' else '0 day' end,'weekday 1'
      ) monday
  )
select d.day,coalesce(sum(t.quantity),0) [Sold Items]
from days d cross join weekMonday wm
left join tablename t
on strftime('%w',t.dateTime) + 0 = d.nr % 7
and date(t.dateTime) between wm.monday and date(wm.monday,'6 day')
group by d.nr,d.day
order by d.nr

对于本年度的总数，您需要一个CTE，该CTE返回月份名称，然后将其加入表进行汇总：

with 
  months as (
    select 1 nr,'JAN' month union all
    select 2 nr,'FEB' union all
    select 3 nr,'MAR' union all
    select 4 nr,'APR' union all
    select 5 nr,'MAY' union all
    select 6 nr,'JUN' union all
    select 7 nr,'JUL' union all
    select 8 nr,'AUG' union all
    select 9 nr,'SEP' union all
    select 10 nr,'OCT' union all
    select 11 nr,'NOV' union all
    select 12 nr,'DEC'
  )
select m.month,0) [Sold Items]
from months m
left join tablename t
on strftime('%m',t.dateTime) + 0 = m.nr
and date(t.dateTime) between date('now','start of year') and date('now','start of year','1 year','-1 day')
group by m.nr,m.month
order by m.nr

,

您可以尝试以下-DEMO

select day,coalesce(sum(quantity),0) as quantity
from 
(select 0 as day union all select 1 union all select 2 union all select 3 union all select 4
union all select 5 union all select 6) as d
left join sales on cast(strftime('%w',dateTime) as int)=day 
group by strftime('%w',dateTime),day
order by day

,

您可以使用以下查询来获取每周日期，我假设everydate具有单个条目，因此不进行分组，否则您可以添加分组依据。

首先，我们将基于输入日期获得每周日历（我已取当前日期） 然后与日历保持联系以获取所需的已售商品信息。

WITH seq(n) AS 
(
  SELECT 0 UNION ALL SELECT n + 1 FROM seq
  WHERE n < DATEDIFF(DAY,(SELECT DATEADD(DAY,2 - DATEPART(WEEKDAY,GETDATE()),CAST(GETDATE() AS DATE)) [Week_Start_Date]),(Select DATEADD(DAY,8 - DATEPART(WEEKDAY,CAST(GETDATE() AS DATE)) [Week_End_Date]))
),CALENDAR(d) AS 
(
  SELECT DATEADD(DAY,n,CAST(GETDATE() AS DATE)) [Week_Start_Date])) FROM seq
)
SELECT coalesce(QUANTITY,0) sold_items,DATENAME(WEEKDAY,d) week_day FROM CALENDAR a left outer join Table_WEEKDAY b
on (a.d = convert(date,b.dateTime))
ORDER BY d
OPTION (MAXRECURSION 0);