如果数组中的对象具有相同的值，则将它们合并到一个对象中

如何解决如果数组中的对象具有相同的值，则将它们合并到一个对象中

我有这个对象数组。每个对象都有唯一的值标签。我想通过标签值对它们进行比较，如果该值与一个具有唯一值的新对象匹配，则应创建该值。

  var test = [{
          isnewLanguage: "false",label: "label1",languages: [{
          language: "English",questions: [{
          choices: "choices1",fields: "false",mainText: "MAinText1",subText: "SubText1"
        }]
        }],numberOfChoices: "5"
        },{
          isnewLanguage: "false",label: "label2",questions: [{
          choices: "choices2",mainText: "MAinText2",subText: "SubText2"
        }]
        }],{
          isnewLanguage: "true",languages: [{
          language: "Italian",questions: [{
          choices: "choicesItalian1",mainText: "MainTextItalian1",subText: "SubTextItalian1"
        }]
        }],numberOfChoices: "false"
        },questions: [{
          choices: "choicesItalian2",mainText: "MAinTextItalian2",subText: "SubTextItalian2"
        }]
        }],languages: [{
          language: "Chinece",questions: [{
          choices: "choicesChinece",mainText: "MainTextChinece1",subText: "SubTextChinece1"
        }]
        }],numberOfChoices: "false"
        }]
    

下面是必需的结构。具有相同标签值的每个对象都应使用新语言附加到一个对象上。

var theRequiredStructure = [{
      isnewLanguage: "true",languagesTest: [{
      language: "English",questions: [{
      choices: "choices1",subText: "SubText1"
    }]
    },{
      language: "Italian",questions: [{
      choices: "choicesItalian1",subText: "SubTextItalian1"
    }]
    },{
      language: "Chinece",questions: [{
      choices: "choicesChinece",subText: "SubTextChinece1"
    }]
    }],numberOfChoices: "false"
    },{
      isnewLanguage: "true",questions: [{
     choices: "choices2",subText: "SubText2"
    }]
    },questions: [{
      choices: "choicesItalian2",mainText: "MainTextItalian2",subText: "SubTextItalian2"
    }]
    },questions: [{
      choices: "choicesChinece2",mainText: "MainTextChinece2",subText: "SubTextChinece2"
    }]
    }],numberOfChoices: "false"
    }

这是我的工作，但显然它仅适用于第一个元素。如何获得所有元素所需的结构？我主要喜欢我可以理解的ES5解决方案。感谢您抽出宝贵的时间

var test = [{
      isnewLanguage: "false",languages: [{
      language: "English",subText: "SubText1"
    }]
    }],numberOfChoices: "5"
    },{
      isnewLanguage: "false",questions: [{
      choices: "choices2",subText: "SubText2"
    }]
    }],languages: [{
      language: "Italian",subText: "SubTextItalian1"
    }]
    }],subText: "SubTextItalian2"
    }]
    }],languages: [{
      language: "Chinece",numberOfChoices: "false"
    }]

var theLanguagesTest = [];
var obj = {};
for (var i = 0; i < test.length; i++) {
  if (test[0].label == test[i].label) {
    obj = test[i]

  }
  for (var j = 0; j < test[i].languages.length; j++) {
    if (test[0].label == test[i].label) {
      theLanguagesTest.push(test[i].languages[j])
      obj.languagesTest = theLanguagesTest
    }
  }
  delete test[i].languages;
  delete test[i].questions;
}




console.log(obj)

解决方法

您的意思是这样的吗？这只是草稿代码，只是向您展示逻辑（一种可能的方式）。阅读下面的代码中的注释

var test = [{
  isnewLanguage: "false",label: "label1",languages: [{
    language: "English",questions: [{
      choices: "choices1",fields: "false",mainText: "MAinText1",subText: "SubText1"
    }]
  }],numberOfChoices: "5"
},{
  isnewLanguage: "false",label: "label2",questions: [{
      choices: "choices2",mainText: "MAinText2",subText: "SubText2"
    }]
  }],{
  isnewLanguage: "true",languages: [{
    language: "Italian",questions: [{
      choices: "choicesItalian1",mainText: "MainTextItalian1",subText: "SubTextItalian1"
    }]
  }],numberOfChoices: "false"
},questions: [{
      choices: "choicesItalian2",mainText: "MAinTextItalian2",subText: "SubTextItalian2"
    }]
  }],languages: [{
    language: "Chinece",questions: [{
      choices: "choicesChinece",mainText: "MainTextChinece1",subText: "SubTextChinece1"
    }]
  }],numberOfChoices: "false"
}];
        
        
// New array
const result = [];
// Map object to map key -> result array index
const map = {};

// Simple loop     
for(let i = 0; i < test.length; i++) {
  // If map contains key with current label
  // then we have it in result array
  if(map[test[i].label] && result[map[test[i].label]] === 0 || result[map[test[i].label]]) {
    // Push same label languages content to results array languageTests subarray
    result[map[test[i].label]].languageTests.push(test[i].languages[0]);
  } else {
    // Else create map record
    map[test[i].label] = Object.keys(map).length;
    // Copy and modify current object
    const item = test[i];
    // Create languageTests sub array
    item.languageTests = [];
    // Copy languages object there
    item.languageTests.push(item.languages[0]);
    // delete languages
    delete item.languages;
    // Push re-formed item to results
    result.push(item);
  }
}

// Log
console.log(result);

,

您也可以这样做：

var test = [{
    isnewLanguage: "false",languages: [{
        language: "English",questions: [{
            choices: "choices1",subText: "SubText1"
        }]
    }],{
    isnewLanguage: "false",questions: [{
            choices: "choices2",subText: "SubText2"
        }]
    }],{
    isnewLanguage: "true",languages: [{
        language: "Italian",questions: [{
            choices: "choicesItalian1",subText: "SubTextItalian1"
        }]
    }],questions: [{
            choices: "choicesItalian2",subText: "SubTextItalian2"
        }]
    }],languages: [{
        language: "Chinece",questions: [{
            choices: "choicesChinece",subText: "SubTextChinece1"
        }]
    }],numberOfChoices: "false"
}]

var byUniqueLabels = {};
var labelsArray = [];

for (var i = 0; i < test.length; i++) {
    if (byUniqueLabels[test[i].label] == "" || byUniqueLabels[test[i].label] == undefined) {
        byUniqueLabels[test[i].label] = { 'isnewLanguage': test[i].isnewLanguage,'label': test[i].label,languagesTest: [] };
    }
    for (var j = 0; j < test[i].languages.length; j++) {
        byUniqueLabels[test[i].label].languagesTest.push(test[i].languages[j]);
    }
}

for (label in byUniqueLabels) {
    labelsArray.push(byUniqueLabels[label]);
}

console.log(labelsArray);