在tkinter中，当我运行搜索并将结果显示为新标签时，如何从一个功能中删除标签？

如何解决在tkinter中，当我运行搜索并将结果显示为新标签时，如何从一个功能中删除标签？

我有一个函数，当我的窗口第一次弹出时显示表中的数据：

def query():
    conn = sqlite3.connect('movie_catalog.db')
    # Create cursor
    c = conn.cursor()

# Query the database
    c.execute("SELECT *,oid FROM movies ORDER BY title ASC")
    records = c.fetchall()

    for index,x in enumerate(records):
        num = 0
        for y in x:
            query_label = Label(root,text=y)
            query_label.grid(row=index + 2,column=num,pady=2)
            num += 1

    # Commit our changes
    conn.commit()

    # Close database connection
    conn.close()

我正在运行循环，以使表中的每一行数据在窗口的新行中显示。但是，当我运行以下搜索功能时，我希望它们消失：

def search_movies():
    # Create a database or connect to one
    conn = sqlite3.connect('movie_catalog.db')
    # Create cursor
    c = conn.cursor()

    selected = drop.get()
    if selected == "Search by":
        test = Label(root,text="Please make a selection")
        test.grid(row=0,column=6)
    if selected == "Title":
        sql = "SELECT * FROM movies WHERE title=?"
    if selected == "Year":
        sql = "SELECT * FROM movies WHERE year=?"
    if selected == "Genre":
        sql = "SELECT * FROM movies WHERE genre=?"
    if selected == "Director":
        sql = "SELECT * FROM movies WHERE director=?"
    if selected == "Cast":
        sql = "SELECT * FROM movies WHERE cast=?"
    if selected == "Tags":
        sql = "SELECT * FROM movies WHERE tags=?"

    searched = search_box.get()
    caps = searched.title()
    t = (caps,)
    result = c.execute(sql,t)
    result = c.fetchall()
    if result:
        for index,x in enumerate(result):
            num = 0
            for y in x:
                searched_label = Label(root,text=y)
                searched_label.grid(row=index + 2,pady=2)
                num += 1

    if not result:
        no_result = Label(root,text="Movie not found")
        no_result.grid(row=2,column=2)

    # Commit our changes
    conn.commit()

    # Close database connection
    conn.close()

此搜索功能实质上是设置为以与第一个功能相同的格式显示结果，但是我需要原始标签消失，因为我的搜索结果与它们重叠。有没有办法从第一个函数中破坏显示？