如何解决是否可以在一行上打印一个不断更新的变量?
这只是一个简单的例子,
import time
for i in range (1,11):
print(i)
time.sleep(1)
此代码计数为10,但是每个打印的i
值都在新行上。是否可以将它们全部打印在第一行,并在每次打印新印刷时都删除该当前编号,以便一次计数到10?
解决方法
在要打印的数字前添加'\ r',这将返回回车并覆盖最后一行:
import time
for i in range (1,11):
print(f'\r{i}',end='')
time.sleep(1)
# Add print after loop for a new line,when finishing
print()
,
您可以使用sys.stdout.write。
const result = [{
"id": 998,"client": {
"id": "AF01072","name": "Vivek","lastName": "Joshi","phone": 123
},"membership": {
"type": "Semi-Annually","price": 18000
},"start_date": "2019-11-19","end_date": "2020-05-16","payment": 12000,"balance": 0
},{
"id": 1004,"membership": {
"type": "Annually","price": 30000
},"start_date": "2020-08-27","end_date": "2021-08-27","payment": 30000,"balance": 5000,},{
"id": 1005,"client": {
"id": "AF01073","name": "Some Other",}
].reduce((acc,item,i) => {
if (i == 0) {
acc.push(constructCorrectObject(item));
return acc;
}
let foundItem = acc.find(it => it.id === item.client.id);
if (foundItem) {
addMemeberShipDetails(foundItem,item);
return acc;
} else {
acc.push(constructCorrectObject(item));
return acc;
}
},[]);
function constructCorrectObject(item) {
return {
"id": item.client.id,"name": item.client.name,"lastName": item.client.lastName,"phone": item.client.phone,"membership": [{
"id": item.id,"type": item.membership.type,"price": item.membership.price,"start_date": item.start_date,"end_date": item.end_date,"payment": item.payment,"balance": item.balance,}]
}
}
function addMemeberShipDetails(acc,item) {
acc.membership.push({
"id": item.id,});
}
console.log(result);
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