如何解决Python：嵌套JSON列表
这是我的JSON文档中的示例JSON对象：
[{
"_id": "COVERAGE_0025","coverageName": "windStormHailDeductible","coverageResponse": "15000","insuranceLine": "COMMERCIAL","coverageCategory": "DEDUCTIBLE","splitCoverages": null,"carriers": [{
"carrierId": "CNINCO","states": null,"excludedStates": [
"FL"
],"industries": null,"excludedIndustries": null,"products": [
"BOP","WC"
]
}]
我需要将coverageName内除_id和coverages以外的所有内容归为一组。
这是我想要的输出：
[{
"_id": "COVERAGE_0025","coverages": [{
"coverageResponse": "15000","carriers": [{
"carrierId": "CNINCO","excludedStates": [
"FL"
],"products": [
"BOP","WC"
]
}]
}]
}]
解决方法
类似的东西呢？
class HeaderComponent extends Component {
render() {
let { isLoginSuccess } = this.props;
...
return (
<header>
<nav className="navbar navbar-expand-md navbar-dark bg-dark">
<div><a href="http://localhost:3000" className="navbar-brand">Todo Management</a></div>
<ul className="navbar-nav">
{isLoginSuccess && <li><Link className="nav-link" to="/welcome/in28minutes">Home</Link></li>}
...
</nav>
</header>
)
}
}
输出：
fixed = ["_id","coverageName"]
d_new = {}
for elem in fixed:
d_new[elem] = d[elem]
d_new["coverages"] = [{}]
for elem in d.keys():
if elem not in fixed:
d_new["coverages"][0][elem] = d[elem]
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