如何解决将项目提取到R tibble中的特定位置
def __init__(self,*args,**kwargs):
self.user = kwargs.pop('user',None)
super(ContactResource,self).__init__(*args,**kwargs)
company = fields.Field(column_name='company')
class Meta:
model = Contact
skip_unchanged = True
report_skipped = True
exclude =('is_active','created_by')
export_order = ('id','first_name','last_name','email','phone','address','description','company','created_on','website','job_title','birthday')
def after_import_instance(self,instance,new,**kwargs):
instance.created_by = self.user # kwargs['user']
def import_field(self,field,obj,data):
field_name = self.get_field_name(field)
method = getattr(self,'clean_%s' % field_name,None)
if method is not None:
obj = method(field,data)
super(ContactResource,self).import_field(field,data)
def clean_company(self,data):
name = data[field.column_name]
company,created = Company.objects.get_or_create(name=name,created_by=self.user)
obj.company = company
return obj
如何提取library(tibble)
x <- tibble(c('a','b','c'))
的值?如果我设置x[1,]
,它会给我一个1x1的小滴。我不要那个。我只想要值“ a”。
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。