如何解决等待后解锁如何发生
我写了一个小程序来交替打印奇偶数,但是有一个问题:
由于线程应在await
调用中等待,因此可重入锁定如何被解锁?
public class Worker implements Runnable
{
private ReentrantLock rLock = null;
private Condition condition = null;
private String name;
volatile static boolean isEvenTurn = true;
public Worker(String name,ReentrantLock rLock,Condition condition)
{
this.name = name;
this.rLock = rLock;
this.condition = condition;
}
@Override
public void run()
{
try
{
if(name.equals("ODD"))
printOdd();
else
printEven();
}
catch(Exception e) { e.printStackTrace();}
}
private void printOdd() throws Exception
{
while(isEvenTurn);
for(int i=1;i<10;i+=2)
{
try
{
rLock.lock();
System.out.println(i);
}
catch(Exception e) {e.printStackTrace();}
finally
{
condition.signal();
condition.await();
rLock.unlock();
}
}
}
private void printEven() throws Exception
{
for(int i=0;i<10;i+=2)
{
try
{
rLock.lock();
System.out.println(i);
isEvenTurn = false;
}
catch(Exception e) {e.printStackTrace();}
finally
{
condition.signal();
condition.await();
rLock.unlock();
}
}
}
public static void main(String[] args)
{
ReentrantLock rLock = new ReentrantLock();
ExecutorService service = Executors.newFixedThreadPool(2);
Condition c = rLock.newCondition();
Worker oddPrinter = new Worker("ODD",rLock,c);
Worker evenPrinter = new Worker("EVEN",c);
service.execute(evenPrinter);
service.execute(oddPrinter);
service.shutdown();
}
}
解决方法
在printEven()方法中,添加以下行:在finally块中:
finally
{
condition.signal();
if(i < 10)condition.await();
rLock.unlock();
}
通过添加此条件,当您的 我= 10,您的线程将不再等待。
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