如何解决为什么当我在node.js代码中使用sql时出现语法错误
"SELECT IF (EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME = `"+message.author.id+"` ));"
此语句中有一个语法错误,我似乎无法识别出任何想法?
错误:
Something is wrong in your syntax near ') LIMIT 0,25' in line 2
我在node.js代码中使用此mysql语句
con.query("SELECT IF (EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME = `"+message.author.id+"` ));",async function (err,result) {
console.log(result);
if (err) throw err;
if(result== undefined)
{
con.query("CREATE TABLE `"+message.author.id+"` ( id int PRIMARY KEY NOT NULL AUTO_INCREMENT,anime_name varchar(255),date DATE,count int(11),);");
}
解决方法
这是因为如果您要进行串联,那么串联是错误的。
let a = "SELECT IF (EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME ="+message.author.id+"));"
//In case you want to do it as template string it should be like
let a = `SELECT IF (EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME = ${message.author.id} ));`
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