单击任何复选框只能激活一个字段?

如何解决单击任何复选框只能激活一个字段?

我正在尝试制作一个表格,其中每个单独的复选框都有一个数字输入字段,该字段仅在选中该复选框时才会显示。到目前为止,我已经知道了:

  <!-- Option1 -->
                      <div class="form-row">
                        <div class="form-group col-md-8">
                          <div class="form-check">
                            <input class="form-check-input showman" type="checkbox" onchange="showqt()" value="Button Chicken Amritsari" id="c1">
                            <label class="form-check-label" for="c1">
                              Button Chicken Amritsari<i><br>(Boneless) Serves 2<br>INR 290</i>
                            </label>
                          </div>
                        </div>
                          <div class="form-group col-md-4 " id="ifYes" style="display: none; float:right;">
                            <!-- <label for="qtcounter">Quantity:</label> -->
                            <div class="input-group" id="qtcounter">
                              <input type="button" value="-" class="button-minus" data-field="quantity">
                              <input type="number" step="1" max="" value="1" name="quantity" class="quantity-field">
                              <input type="button" value="+" class="button-plus" data-field="quantity">
                            </div>
                          </div>
                      </div>
                      <!-- Option 1 ends -->
                      <div class="form-row">
                        <div class="form-group col-md-8">
                          <div class="form-check">
                            <input class="form-check-input showman" type="checkbox" onchange="showqt()" value="Chicken Korma Awadhi" id="c2">
                            <label class="form-check-label" for="c2">
                              Chicken Korma Awadhi<br><i> (Boneless) Serves 2<br>INR 290</i>
                            </label>
                          </div>
                        </div>
                          <div class="form-group col-md-4" id="ifYes" style="display: none; float:right;">
                            <!-- <label for="qtcounter">Quantity:</label> -->
                            <div class="input-group" id="qtcounter">
                              <input type="button" value="-" class="button-minus" data-field="quantity">
                              <input type="number" step="1" max="" value="1" name="quantity" class="quantity-field">
                              <input type="button" value="+" class="button-plus" data-field="quantity">
                            </div>
                          </div>
                      </div>

这是我的JS:

function showqt(){
  if ($('.showman').is(":checked")) {
    document.getElementsByClassName('className')
    document.getElementById('ifYes').style.display = 'inline';
  }
  else {
    document.getElementById('ifYes').style.display = 'none';
  }
}

现在,只要我只有一个复选框,它就可以正常工作。但是,当我添加更多复选框时,无论单击哪个复选框,都只单击第一个复选框的输入字段。我希望根据是否选中复选框来显示每个复选框的输入字段。

是否有全局方法来执行此操作,还是需要为每个复选框编写自定义JS?

解决方法

     <!-- Option1 -->
                          <div class="form-row">
                            <div class="form-group col-md-8">
                              <div class="form-check">
                                <input class="form-check-input showman" type="checkbox" onchange="showqt(this)" value="Button Chicken Amritsari" id="c1">
                                <label class="form-check-label" for="c1">
                                  Button Chicken Amritsari<i><br>(Boneless) Serves 2<br>INR 290</i>
                                </label>
                              </div>
                            </div>
                              <div class="form-group col-md-4 " id="ifYes" style="display: none; float:right;">
                                <!-- <label for="qtcounter">Quantity:</label> -->
                                <div class="input-group" id="qtcounter">
                                  <input type="button" value="-" class="button-minus" data-field="quantity">
                                  <input type="number" step="1" max="" value="1" name="quantity" class="quantity-field">
                                  <input type="button" value="+" class="button-plus" data-field="quantity">
                                </div>
                              </div>
                          </div>
                          <!-- Option 1 ends -->
                          <div class="form-row">
                            <div class="form-group col-md-8">
                              <div class="form-check">
                                <input class="form-check-input showman" type="checkbox" onchange="showqt(this)" value="Chicken Korma Awadhi" id="c2">
                                <label class="form-check-label" for="c2">
                                  Chicken Korma Awadhi<br><i> (Boneless) Serves 2<br>INR 290</i>
                                </label>
                              </div>
                            </div>
                              <div class="form-group col-md-4" id="ifYes" style="display: none; float:right;">
                                <!-- <label for="qtcounter">Quantity:</label> -->
                                <div class="input-group" id="qtcounter">
                                  <input type="button" value="-" class="button-minus" data-field="quantity">
                                  <input type="number" step="1" max="" value="1" name="quantity" class="quantity-field">
                                  <input type="button" value="+" class="button-plus" data-field="quantity">
                                </div>
                              </div>
                          </div>

function showqt(obj){
    if ($(obj).is(":checked")) {
      
      jQuery(obj).parents(".form-row").find("#ifYes").show();
    }
    else {
        jQuery(obj).parents(".form-row").find("#ifYes").hide();
    }
  }

它将起作用。

,

只需使用jQuery方法:

$('#ifYes').css('display','block'); and $('#ifYes').css('display','none');
,

您也可以使用:checked伪选择器仅使用CSS来实现此目的。下面的代码段使用~通用同级组合器来切换计数器的可见性。

.form-row {
  padding-top: 1rem;
}
.counter {
  display: none;
 }
.showman:checked ~ .counter{
  display: block;
}
<!-- Option1 -->
<div class="form-row">

    <input class="form-check-input showman" type="checkbox" value="Button Chicken Amritsari" id="c1">
    <label class="form-check-label" for="c1">
      Button Chicken Amritsari<i><br>(Boneless) Serves 2<br>INR 290</i>
    </label>
    
  <div class="counter">
    <input type="button" value="-" class="button-minus" data-field="quantity">
    <input type="number" step="1" max="" value="1" name="quantity" class="quantity-field">
    <input type="button" value="+" class="button-plus" data-field="quantity">
  </div>
</div>
<!-- Option 1 ends -->

<div class="form-row">

    <input class="form-check-input showman" type="checkbox" value="Chicken Korma Awadhi" id="c2">
    <label class="form-check-label" for="c2">
      Chicken Korma Awadhi<br><i> (Boneless) Serves 2<br>INR 290</i>
    </label>

  <div class="counter">
    <input type="button" value="-" class="button-minus" data-field="quantity">
    <input type="number" step="1" max="" value="1" name="quantity" class="quantity-field">
    <input type="button" value="+" class="button-plus" data-field="quantity">
  </div>
</div>

版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。

相关推荐


依赖报错 idea导入项目后依赖报错,解决方案:https://blog.csdn.net/weixin_42420249/article/details/81191861 依赖版本报错:更换其他版本 无法下载依赖可参考:https://blog.csdn.net/weixin_42628809/a
错误1:代码生成器依赖和mybatis依赖冲突 启动项目时报错如下 2021-12-03 13:33:33.927 ERROR 7228 [ main] o.s.b.d.LoggingFailureAnalysisReporter : *************************** APPL
错误1:gradle项目控制台输出为乱码 # 解决方案:https://blog.csdn.net/weixin_43501566/article/details/112482302 # 在gradle-wrapper.properties 添加以下内容 org.gradle.jvmargs=-Df
错误还原:在查询的过程中,传入的workType为0时,该条件不起作用 &lt;select id=&quot;xxx&quot;&gt; SELECT di.id, di.name, di.work_type, di.updated... &lt;where&gt; &lt;if test=&qu
报错如下,gcc版本太低 ^ server.c:5346:31: 错误:‘struct redisServer’没有名为‘server_cpulist’的成员 redisSetCpuAffinity(server.server_cpulist); ^ server.c: 在函数‘hasActiveC
解决方案1 1、改项目中.idea/workspace.xml配置文件,增加dynamic.classpath参数 2、搜索PropertiesComponent,添加如下 &lt;property name=&quot;dynamic.classpath&quot; value=&quot;tru
删除根组件app.vue中的默认代码后报错:Module Error (from ./node_modules/eslint-loader/index.js): 解决方案:关闭ESlint代码检测,在项目根目录创建vue.config.js,在文件中添加 module.exports = { lin
查看spark默认的python版本 [root@master day27]# pyspark /home/software/spark-2.3.4-bin-hadoop2.7/conf/spark-env.sh: line 2: /usr/local/hadoop/bin/hadoop: No s
使用本地python环境可以成功执行 import pandas as pd import matplotlib.pyplot as plt # 设置字体 plt.rcParams[&#39;font.sans-serif&#39;] = [&#39;SimHei&#39;] # 能正确显示负号 p
错误1:Request method ‘DELETE‘ not supported 错误还原:controller层有一个接口,访问该接口时报错:Request method ‘DELETE‘ not supported 错误原因:没有接收到前端传入的参数,修改为如下 参考 错误2:cannot r
错误1:启动docker镜像时报错:Error response from daemon: driver failed programming external connectivity on endpoint quirky_allen 解决方法:重启docker -&gt; systemctl r
错误1:private field ‘xxx‘ is never assigned 按Altʾnter快捷键,选择第2项 参考:https://blog.csdn.net/shi_hong_fei_hei/article/details/88814070 错误2:启动时报错,不能找到主启动类 #
报错如下,通过源不能下载,最后警告pip需升级版本 Requirement already satisfied: pip in c:\users\ychen\appdata\local\programs\python\python310\lib\site-packages (22.0.4) Coll
错误1:maven打包报错 错误还原:使用maven打包项目时报错如下 [ERROR] Failed to execute goal org.apache.maven.plugins:maven-resources-plugin:3.2.0:resources (default-resources)
错误1:服务调用时报错 服务消费者模块assess通过openFeign调用服务提供者模块hires 如下为服务提供者模块hires的控制层接口 @RestController @RequestMapping(&quot;/hires&quot;) public class FeignControl
错误1:运行项目后报如下错误 解决方案 报错2:Failed to execute goal org.apache.maven.plugins:maven-compiler-plugin:3.8.1:compile (default-compile) on project sb 解决方案:在pom.
参考 错误原因 过滤器或拦截器在生效时,redisTemplate还没有注入 解决方案:在注入容器时就生效 @Component //项目运行时就注入Spring容器 public class RedisBean { @Resource private RedisTemplate&lt;String
使用vite构建项目报错 C:\Users\ychen\work&gt;npm init @vitejs/app @vitejs/create-app is deprecated, use npm init vite instead C:\Users\ychen\AppData\Local\npm-