如何解决使用JavaScript的哈希表实现
我正在尝试使用javascript实现哈希表。目前,一切正常,但是我在给定特定键的情况下无法使用get方法检索哈希表中的值。我正在使用线性探测以避免碰撞。当我对键“ Alejandro”进行哈希处理时,我会将键映射到0索引。然后,将其添加到哈希表中。然后我尝试“ Rosalby”,它也映射到0索引。我使用线性探测来找到下一个可用的插槽,在本例中,空索引为1,然后将Rosalby的值放在该插槽中。到目前为止,看来我的碰撞管理得很好。然而;当我尝试在get方法中获取值时,无法获得正确的值,这就是哈希表的样子。
此外,我想提到的是,我使哈希表的大小变大了,并且给定了特定的键,我得到了正确的值,这仅仅是因为我没有碰撞。预先谢谢你。
// Hash table implementation
class HashTable {
// constructor functio
constructor(size) {
this.size = size;
this.buckets = this.initArray(size);
this.limit = 0;
}
// init array function
initArray(size) {
// init an array
const array = [];
// populate the array base on the size
for (let i = 0; i < size; i++) {
// push null to the array
array.push(null);
}
// return the array
return array;
}
// mapping key to index
hash(key) {
let total = 0;
// get unique code of character in the string
for (let i = 0; i < key.length; i++) {
let keyCode = key.charCodeAt(i)
// console.log("Key code:",keyCode)
// sum up the unique code
total += keyCode;
// console.log(total);
}
// mod the total to the size of the hash table
const hashIndex = total % this.size;
// return that index
return hashIndex;
}
// put method
put(key,value) {
// throw an erro if hashTable is full
if (this.limit >= this.size) throw "Hash Table is full";
// hash the key
let hashIndex = this.hash(key);
// console.log(hashIndex);
// linear probing
while (this.buckets[hashIndex] != null) {
hashIndex++;
hashIndex = hashIndex % this.size;
}
// add the value at that key to the buckets array
this.buckets[hashIndex] = value;
// increase the limit
this.limit++;
}
// get method
get(key) {
// hash the key
let hashIndex = this.hash(key);
let value = this.buckets[hashIndex];
// return the value at that index
return value;
}
} // end of hash table
// sanity check
const ht = new HashTable(3);
console.log(ht);
// ht.hash("Rosalby");
console.log();
ht.put("Alejandro","555-5555");
ht.put("Rosalby","123-1231");
ht.put("Lalaland","000-0000");
// ht.put("Lalaland","919-1919");
console.log();
console.log(ht);
console.log("Alejandro:",ht.get("Alejandro"),"Rosalby:",ht.get("Rosalby"),"Lalaland:",ht.get("Lalaland"));
解决方法
这是哈希表的快速实现:
class HashTable
{
constructor(getHash)
{
if(!getHash) throw "Argument is null: getHash";
this.getHash = getHash;
this.buckets = {};
this._count = 0;
}
// throws an exception if the key already exists
add(key,value)
{
const hashCode = this.getHash(key);
const bucket = this.buckets[hashCode];
if(!bucket)
{
this.buckets[hashCode] = [{key,value}];
++this._count;
return;
}
for(let length = bucket.length,i = 0; i < length; ++i)
{
const item = bucket[i];
if(item.key == key) throw "Duplicate key.";
}
bucket.push({key,value});
++this._count;
}
// replaces the value if the key already exists
set(key,i = 0; i < length; ++i)
{
const item = bucket[i];
if(item.key == key)
{
item.value = value;
return;
}
}
bucket.push({key,value});
++this._count;
}
get(key,defaultValue)
{
const hashCode = this.getHash(key);
const bucket = this.buckets[hashCode];
if(!bucket) return defaultValue;
for(let length = bucket.length,i = 0; i < length; ++i)
{
const item = bucket[i];
if(item.key == key) return item.value;
}
return defaultValue;
}
has(key)
{
const hashCode = this.getHash(key);
const bucket = this.buckets[hashCode];
if(!bucket) return false;
for(let length = bucket.length,i = 0; i < length; ++i)
{
const item = bucket[i];
if(item.key == key) return true;
}
return false;
}
get count()
{
return this._count;
}
}
HashTable.unitTests = function()
{
function getHash(value)
{
const stringValue = String(value);
let result = 0;
for(let length = stringValue.length,i = 0; i < length; ++i) result ^= stringValue.charCodeAt(i);
return result;
}
let ht;
// empty
ht = new HashTable(getHash);
if (ht.count != 0) throw "failed";
if (ht.has(null)) throw "failed";
if (ht.has("")) throw "failed";
if (ht.get(null) != void (0)) throw "failed";
if (ht.get("") != void (0)) throw "failed";
if (ht.get(null,1) != 1) throw "failed";
// add new
ht = new HashTable(getHash);
ht.add("a",1);
if (ht.count != 1) throw "failed";
if (!ht.has("a")) throw "failed";
if (ht.get("a") != 1) throw "failed";
// set new
ht = new HashTable(getHash);
ht.set("a",1);
if (ht.count != 1) throw "failed";
if (!ht.has("a")) throw "failed";
if (ht.get("a") != 1) throw "failed";
// add duplicate
ht = new HashTable(getHash);
ht.add("a",1);
try { ht.add("a",1); throw "failed"; } catch (ex) { if (ex != "Duplicate key.") throw "failed"; }
// add+set duplicate
ht = new HashTable(getHash);
ht.add("a",1);
ht.set("a",1);
if (ht.count != 1) throw "failed";
if (!ht.has("a")) throw "failed";
if (ht.get("a") != 1) throw "failed";
// set+add duplicate
ht = new HashTable(getHash);
ht.set("a",1); throw "failed"; } catch (ex) { if (ex != "Duplicate key.") throw "failed"; }
// set duplicate
ht = new HashTable(getHash);
ht.set("a",1);
if (ht.count != 1) throw "failed";
if (!ht.has("a")) throw "failed";
if (ht.get("a") != 1) throw "failed";
// add multiple
ht = new HashTable(getHash);
ht.add("a",1);
ht.add("b",2);
if (ht.count != 2) throw "failed";
if (!ht.has("a")) throw "failed";
if (!ht.has("b")) throw "failed";
if (ht.get("a") != 1) throw "failed";
if (ht.get("b") != 2) throw "failed";
// add with collision
ht = new HashTable(getHash);
ht.add("ab",1); // hash code 3
ht.add("ba",2); // hash code 3
if (ht.count != 2) throw "failed";
if (!ht.has("ab")) throw "failed";
if (!ht.has("ba")) throw "failed";
if (ht.get("ab") != 1) throw "failed";
if (ht.get("ba") != 2) throw "failed";
// set with collision
ht = new HashTable(getHash);
ht.set("ab",1); // hash code 3
ht.set("ba",2); // hash code 3
if (ht.count != 2) throw "failed";
if (!ht.has("ab")) throw "failed";
if (!ht.has("ba")) throw "failed";
if (ht.get("ab") != 1) throw "failed";
if (ht.get("ba") != 2) throw "failed";
}
HashTable.unitTests();
console.log("OK");
<html>
<head>
<script src="HashTable.js"></script>
</head>
<body>
</body>
</html>
一些说明:
- 哈希函数是作为哈希表的配置而有意提供的;使班级更可重用;
- 使用this._count是实施容量限制的更好方法(虽然未实现,但易于添加);
- 单元测试可以扩展更多。但是,我们在这里所拥有的足以表明HashTable类是可操作的;
- ^运算符(按位XOR)通常可以更好地分布所生成的哈希码。参见Why are XOR often used in java hashCode() but another bitwise operators are used rarely?。
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